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2 years ago

Solve the inequality 4(c-3)>10

Mathematics

2 answers:

lora16 [44]2 years ago

6 0

That’s the solution step by step ! Hope it helped ;)

KiRa [710]2 years ago

4 0

C>6 should be the answer

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A kite gets stuck at the top of a vertical tree. The kite's 15 m string

Georgia [21]

Are you good it’s 73.33

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2 years ago

What is the GCF of 21,24,27

yawa3891 [41]

The gcf is 3 because that is thier greatest common factor that isn't 1

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2 years ago

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7. Fin the missing numbers for this rate table. SHOW YOUR WORK

lana [24]

Answer:

Brownies

270

Cooldies

384

Step-by-step explanation:

Brownies

simply multiply the 18 by 3 we get 54 and if we multiply 54 by 5 we get 270.

we multiply it by 5 because in series it skip 1 number to multiply next.

Cooldies

first we multiply 16 by 2 we get 32.

next we multiply 32 by 3 we get 96.

and next we multiply 96 by 4 we get 384.

Simply increment in multiplication.

8 0

3 years ago

A government official is in charge of allocating social programs throughout the city of Vancouver. He will decide where these so

otez555 [7]

Answer: (0.132132, 0.274368)

Step-by-step explanation:

Given : A simple random sample of 123 people living in Gastown and finds that 25 have an annual income that is below the poverty line.

i.e. n= 123

$\hat{p}=\dfrac{25}{123}\approx0.203252$

Critical value for 95% confidence interval : $z_{\alpha/2}=1.96$

Confidence interval for population :

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

i.e. $0.203252\pm (1.96)\sqrt{\dfrac{0.203252(1-0.203252)}{123}}$

$0.203252\pm (1.96)\sqrt{\dfrac{0.203252(1-0.203252)}{123}}\\\\\0.203252\pm0.071118\\\\=(0.20325-0.071118,\ 0.203252+0.071118)\\\\=(0.132132,\ 0.274368)$

Hence, the 95% confidence interval for the true proportion of Gastown residents living below the poverty line : (0.132132, 0.274368)

5 0

3 years ago

there are 4 muffins on each plate. there are 0 plates of lemons muffins. how many lemon muffins are there?

Pie

There would not be any lemon muffins?

3 0

2 years ago

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