A 250 m train travels through a 2km tunnel at 27 km/hr. How long is it from the time the front of the train enters the tunnel, t
o when it completely leaves it?
please explain properly
1 answer:
Answer:
5 min
Step-by-step explanation:
time taken=distance required to travel/speed of train
total distance train have to cover to just left the tunnel is (lenght of tunnel+length of train) =2km+250m
=2250m
speed of train is 27km/hr
multiply 5/18 to convert in m/s
i.e, (5/18)×27=7.5m/s
now time taken =2250m/(7.5m/s)
=300s
and,300s =5min
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Answer:- 2
Step-by-step explanation:
None of the above, it's a hard one alright!
8x^2+5x=-3
8x^2+5x+3=0
after solving this u will get x= (- 5(⁺ ⁻)√-71)/16
Let the dryer cost x.
Then, the washer costs (x-77)
Together, they cost (x) + (x-77) = 873
2x-77 = 873 [subtract 77 from both sides]
2x = 796
x = 398
So the dryer costs $398
3 hours 54 minutes is the answer
