A 250 m train travels through a 2km tunnel at 27 km/hr. How long is it from the time the front of the train enters the tunnel, t
o when it completely leaves it?
please explain properly
1 answer:
Answer:
5 min
Step-by-step explanation:
time taken=distance required to travel/speed of train
total distance train have to cover to just left the tunnel is (lenght of tunnel+length of train) =2km+250m
=2250m
speed of train is 27km/hr
multiply 5/18 to convert in m/s
i.e, (5/18)×27=7.5m/s
now time taken =2250m/(7.5m/s)
=300s
and,300s =5min
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Steps to solve:
x - 5 for x = 15
~Substitute
15 - 5
~Subtract
10
Best of Luck!
45 minutes because it has 4 dots and that’s greater than the rest on the dot plot.
Answer:
this angle's sum is 90°
(3x+40)°+(4x-6)=90°
7x+34=90°
7x=90-34
7x=56
x=56/7
x=8
3x+40 = 3×8+40 = 64°
4x-6 = 4×8-6 = 26°
Tyler.
3/4 is the highest fraction of the four options.
