What two numbers multiplies to 16 and adds to -17?

Mathematics

1 answer:

stepan [7]3 years ago

4 0

-16 and -1 multiply to be 16, but add to be -17

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The perimeter of the triangle below is 97 cm.

Sloan [31]

Answer:

The length of EF = x = 18 cm

Option A is correct.

Step-by-step explanation:

Ware given perimeter of triangle = 97 cm

We need to find length of EF = x = ?

The length of EG = x+7

The length of EF = x

The length of GF = 3x

The formula used is: $Periemter \ of \ triangle= Sum \ of \ all \ sides \ of \ triangle$

Putting values and finding x i.e length of EF

$Periemter \ of \ triangle= Sum \ of \ all \ sides \ of \ triangle\\97=x+7+x+3x\\97-7=5x\\5x=90\\x=\frac{90}{5}\\x=18 \ cm$

So, value of x=18 cm

The length of EF = x = 18 cm

Option A is correct.

4 0

3 years ago

Use the Parabola tool to graph the quadratic function. f(x)=2x^2−12x+19 Graph the parabola by first plotting its vertex and then

Debora [2.8K]

To find the vertex of our parabola, we are going to use the vertex formula: For a quadratic of the form $f(x)=x^2+bx+c$ it vertex $(h,k)$ is given by $h= \frac{-b}{2a}$ , $k=f(h)$ .
We can infet from our parabola that $a=2$ and $b=-12$ . So lets replace those values in our formula:
$h= \frac{-b}{2a}$
$h= \frac{-(-12)}{2(2)}$
$h= \frac{12}{4}$
$h=3$
$k=f(h)=2(3)^2-12(3)+19$
$k=2(9)-36+19$
$k=18-17$
$k=1$
The vertex $(h,k)$ of our parabola is $(3,1)$

Now to find our second point, we are going to evaluate our parabola at $x=0$
$f(0)=2(0)^2-12(0)+19$
$f(0)=0+0+19$
$f(0)=19$
Our second point is $(0,19)$

We can conclude that we can graph the parabola $f(x)=2x^2-12x+19$ using its vertex $(3,1)$ and the point $(0,19)$ as follows: