Answer:
22
Step-by-step explanation:
Working backwards
1+1 then x2 is 4
4+1 then x2 is 10
10+1 then x2 is 22
This is just simple. For example you have a plane of the form x=a, then you just substitute x with a, and you'll get an equation with y and z only, hence you have a 2-d trace of the intersection. It is just similar for y=b and z=c.
(1) At z=1.5, 2x^2 + 5y^2 + 1.5^2 = 4
2x^2 + 5y^2 = 1.75
Now you have an ellipse in the z=1.5 plane as your trace.
(2) At x=1, 2(1)^2 + 5y^2 + z^2 = 4
5y^2 + z^2 = 2
Now you have an ellipse in the x=1 plane as your trace.
(3) At z=0, 2x^2 + 5y^2 + (0)^2 = 4
2x^2 + 5y^2 = 4
Now you have an ellipse in the z=0 plane as your trace.
(4) At y=0, 2x^2 + 5(0)^2 + z^2 = 4
2x^2 + z^2 = 4
Now you have an ellipse in the y=0 plane as your trace.
Answer:
B. (5, ∞)
Step-by-step explanation:
The correct answer choice is marked.
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The absolute value function increases to the right of its vertex. Here, the vertex has been moved to (x, y) = (5, 2). This means the function is increasing for 5 < x.
In interval notation, the domain of increase is (5, ∞).
This equation is a direct variation. If y increases, x increases. The constant of variation is 4 I think. Hope that helped.
Answer:
R(x)= 22
Step-by-step explanation:
