Im pretty sure the answer is 13! :)
Remark
A kite is constructed such that AB = BC and AD = DC. AB = sqrt( (1/2)AC + 18^2) see diagram. AD = sqrt(24^2 + 32^2)
Step One
Solve for AB
1/2 AC = 24 (AC is given as 48)
18 is a given length
AB = sqrt(24^2 + 18^2) = sqrt(576 + 324) = sqrt(900) = 30
Step Two
Find the length of AD
AD = sqrt(32^2 + 24^2) = sqrt(1024 + 576) = sqrt(1600) = 40
Step Three
Find the Perimeter.
P = 2 * 30 + 2*40 = 60 + 80 = 140
P = 140 <<<<< Answer
Answer:
B
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°, thus
p = 180° - (80 + 20)° = 180° - 100° = 80° and
q = 180° - (45 + 55)° = 180° - 100° = 80°
Thus p = q → B
Answer: 14
Step-by-step explanation:
Its the middle line
