Question

Quick algebra 1 question for 10 points!

Answer 1

Answer:

B) x = -7

Step-by-step explanation:

Given equation: $10(x+10)-4=11-5(2x+11)$

Step 1: Distribute $10$ and $-5$ through the parentheses.

$\implies 10(x)+10(10)-4=11-5(2x)-5(11)$

$\implies 10x+100-4=11-10x-55$

Step 2: Simplify (combine like terms).

$\implies 10x+100-4=11-10x-55$

$\implies 10x+96=-44-10x$

Step 3: Add $10x$ to both sides.

$\implies 10x+10x+96=-44-10x+10x$

$\implies 20x+96=-44$

Step 4: Subtract $96$ from both sides.

$\implies 20x+96-96=-44-96$

$\implies 20x=-140$

Step 5: Divide both sides by $20$ to isolate $x$.

$\implies \dfrac{20x}{20}=\dfrac{-140}{20}$

$\implies \boxed{x=-7}$

Answer 2

Answer:

○ $x = -7$

Step-by-step explanation:

Given the equation:

$10(x + 10) - 4 = 11 - 5(2x + 11)$,

to solve for $x$, we have to rearrange the equation to make $x$ its subject.

$10(x + 10) - 4 = 11 - 5(2x + 11)$

⇒ $10x + 100 - 4 = 11 - 10x -55$      [expand brackets]

⇒ $10x + 96 = -44 - 10x$

⇒ $10x + 10x + 96 = -44$                   [add $10x$ to both sides]

⇒ $20x + 96 = -44$

⇒ $20x = -44 - 96$                             [subtract 96 from both sides]

⇒ $20x = -140$

⇒ $x = \frac{-140}{20}$                                        [divide both sides by 20]

⇒ $x = \bf-7$