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zavuch27 [327]
3 years ago
7

Two friends are collecting cards. Frank has 7 more than half the number of cards as his friend. Together they have 42 cards. How

many cards does each friend have?
Mathematics
1 answer:
Naddika [18.5K]3 years ago
7 0

Answer:

The number of cards Frank has is 18 and the number of cards his friend has is 24.

Step-by-step explanation:

<u><em>The correct question is </em></u>

Two friends are collecting cards. Frank has 6 more than half the number of cards as his friend. Together they have 42 cards. How many cards does each friend have?

Let

x ----> the number of cards that Frank has

y ----> the number of cards that his friend has

we know that

Together they have 42 cards

x+y=42 ----> equation A

Frank has 6 more than half the number of cards as his friend

x=\frac{y}{2} +6 ---> equation B

Solve the system by substitution    

Substitute equation B in equation A

\frac{y}{2} +6+y=42

solve for y

\frac{3}{2}y=42-6\\\\\frac{3}{2}y=36\\\\y=36(2)/3=24

<em>Find the value of x</em>

x=\frac{24}{2} +6=18

therefore

The number of cards Frank has is 18 and the number of cards his friend has is 24.

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Citrus2011 [14]

Answer: The answer is 18

Step-by-step explanation:

The figures are the same shape, just one is longer. As you can see, the smallest side on the smaller figure is 3 inches. If you look at the larger figure, the smallest side is 6 inches. From this, you can see that you are supposed to multiply the lengths on the smaller figure by 2, to the lengths for the larger figure.

6 0
3 years ago
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Geometry help please........
svp [43]
Let m = 10 and n = 2

We know:

y^2 = (m+n).m

y^2 = (10+2).10

y^2 = 120

y = √(120)

Then,

m^2 + x^2 = y^2

10^2 + x^2 = ( √( 120) )^2

100 + x^2 = 120

x^2 = 120 - 100

x^2 = 20

x = √(20)

x = √(4×5)

x = √(4) × √(5)

x = 2√(5)

I hope this has helped!
4 0
3 years ago
Twice the sum of a number and 11 is 34.
Maru [420]

<u>Answer:</u>

  • The number is 6.

<u>Solution:</u>

  • 2(x + 11) = 34
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  • => x = 12/2
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BrainiacUser1357

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Kim purchased 6 small containers of potato salad and Seth purchased 2 extra large containers of potato salad. What is the differ
icang [17]

I am assuming that the attached is the complete question and we need to get the information from the table.

From the table we know the below fact:

1 \; small \; container \; of \; potato \; salad \; Weighs \; \frac{2}{8} \; pounds\\\\1 \; extra \; large \; container \; of \; potato \; salad \; Weighs \; \frac{9}{8}  \; pounds

Weight \; of \; 6 \; small \; container = 6 \times \frac{2}{8}  = \frac{12}{8}  \; pounds\\\\Weight \; of \; 2 \; Extra \; large \; container = 2 \times \frac{9}{8} \; = \; \frac{18}{8}  \; pounds

Conclusion:

The difference in weights, in pounds of Kim’s and Seth’s purchases is given below:

\frac{18}{8} - \frac{12}{8} =  \frac{18-12}{8}   = \frac{6}{8}  \\\\Simplifying \; the \; fraction \; dividing \; by \; 2 \; on \; both \; numerator \; and \; denominator\\\\ \frac{6 \div 2}{8 \div 2}  = \frac{3}{4}

Final answer : <em><u>0.75 pounds</u></em>

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