Answer:
2
Step-by-step explanation:
Simplify the following:
(-(2 + 2/3))/(-(1 + 1/3))
(-(2 + 2/3))/(-(1 + 1/3)) = (-1)/(-1)×(2 + 2/3)/(1 + 1/3) = (2 + 2/3)/(1 + 1/3):
(2 + 2/3)/(1 + 1/3)
Put 1 + 1/3 over the common denominator 3. 1 + 1/3 = 3/3 + 1/3:
(2 + 2/3)/(3/3 + 1/3)
3/3 + 1/3 = (3 + 1)/3:
(2 + 2/3)/((3 + 1)/3)
3 + 1 = 4:
(2 + 2/3)/(4/3)
Put 2 + 2/3 over the common denominator 3. 2 + 2/3 = (3×2)/3 + 2/3:
((3×2)/3 + 2/3)/(4/3)
3×2 = 6:
(6/3 + 2/3)/(4/3)
6/3 + 2/3 = (6 + 2)/3:
((6 + 2)/3)/(4/3)
6 + 2 = 8:
(8/3)/(4/3)
Multiply the numerator by the reciprocal of the denominator, (8/3)/(4/3) = 8/3×3/4:
(8×3)/(3×4)
(8×3)/(3×4) = 3/3×8/4 = 8/4:
8/4
The gcd of 8 and 4 is 4, so 8/4 = (4×2)/(4×1) = 4/4×2 = 2:
Answer: 2
Answer: 17.832 kg
Solution: (4458 grams)*(4 books)*
= 17.832 kg
Answer:
a) there is s such that <u>r>s</u> and s is <u>positive</u>
b) For any <u>r>0</u> , <u>there exists s>0</u> such that s<r
Step-by-step explanation:
a) We are given a positive real number r. We need to wite that there is a positive real number that is smaller. Call that number s. Then r>s (this is equivalent to s<r, s is smaller than r) and s is positive (or s>0 if you prefer). We fill in the blanks using the bold words.
b) The last part claims that s<r, that is, s is smaller than r. We know that this must happen for all posirive real numbers r, that is, for any r>0, there is some positive s such that s<r. In other words, there exists s>0 such that s<r.
Answer:
Step-by-step explanation:
<u>Exponential function:</u>
<u>Ordered pairs given:</u>
<u>Substitute x and y values to get below system:</u>
<u>Divide the second equation by the first one and solve for b:</u>
- 80/10 = b³
- b³ = 8
- b = ∛8
- b = 2
<u>Use the first equation and find the value of a:</u>
<u>The function is:</u>
Answer:
t(c) = 3.355
Step-by-step explanation:
We assume a normal distribution, and with sample size n = 9 we should follow a t -student test on both tails since the FDA is interested in determining if the amount of drug absorbed is different from 3.5 micrograms.
Therefore if α = 0,01 that means that confidence interval is 99 % or 0,99
Finally with α/2 = 0,005 and 8 degrees of freedom we find in t-student table t(c) = 3.355
