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ICE Princess25 [194]
3 years ago
12

How do you find the missing height of a triangle?

Mathematics
2 answers:
g100num [7]3 years ago
8 0

Answer:

Use the Pythagorean theorem

Step-by-step explanation:

The pythagorean theorem is a^{2} +b^{2} =c^{2} where a is a height, b is a height, and c is the hypotenuse, which is the longest side of a triangle. For example, if the triangle has two side with lengths of three and four we would put them into the equation to get:

3^{2} +4^{2} =c^{2}

Simplify the equation to get:

9+16=c^2

Add 16 and 9 to get 25 and take the square root of both sides:

\sqrt{25} =c

The sqrt of 25 is 5. Therefore, the length of the hypotenuse, or c, is 5.

maks197457 [2]3 years ago
4 0

Answer:

Plug your values into the equation A=1/2bh and do the math. First multiply the base (b) by 1/2, then divide the area (A) by the product. The resulting value will be the height of your triangle.

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3 years ago
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Brrunno [24]

Answers:

(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\\\(f \circ g)(2) = \sqrt{401}\\\\

========================================================

Work shown for part 1

f(x) = \sqrt{x^2-2x+2}\\\\f(g(x)) = \sqrt{(g(x))^2-2(g(x))+2}\\\\f(g(x)) = \sqrt{(-6x-7)^2-2(-6x-7)+2}\\\\f(g(x)) = \sqrt{36x^2+84x+49+12x+14+2}\\\\f(g(x)) = \sqrt{36x^2+96x+65}\\\\(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\

----------------------------------

Work shown for part 2

(f \circ g)(x) = \sqrt{36x^2+96x+65}\\\\(f \circ g)(2) = \sqrt{36(2)^2+96(2)+65}\\\\(f \circ g)(2) = \sqrt{401}\\\\

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2 years ago
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Answer:

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Step-by-step explanation:

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Read 2 more answers
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