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masha68 [24]
3 years ago
5

If a sample of 77 students were taken from a population of 950 students, o^2 could refer to the variance of how many of the stud

ents height
Mathematics
2 answers:
MAVERICK [17]3 years ago
4 0
<span>variance of </span>950 students
mixas84 [53]3 years ago
4 0

Answer with explanation:

Sample of Students Chosen =950----N

Total Number of students = 77

Probability of choosing a student from 77 students, that is Probability of Success

             =\frac{77}{950}------P

Probability of Failure ,that is choosing a student from , 950-77=873, students

        =\frac{873}{950}-----Q

\text{Variance}(\sigma)^2=\sqrt{NPQ}\\\\=\sqrt{950 \times \frac{77}{950}\times \frac{873}{950}}\\\\=\sqrt{873 \times \frac{77}{950}}\\\\=70.7589

Approximately ,70 or 71 Students refer to the variance of of the students height.

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a small rocket is shot from the edge of a cliff suppose that after t seconds the rocket is y meters above the cliff where y=30t-
Natalka [10]

Answer:

Greatest height: 45 meters

Time for greatest height: 3 seconds

Height after 5 seconds: 25 meters above the cliff

Time for height of 40 meters: 7.123 seconds

Height after 7 seconds: -35 meters (35 meters below the cliff)

Step-by-step explanation:

to find the maximum height, we need to calculate the derivative of y in relation to t and then find when dy/dt = 0:

dy/dt = 30 - 10t = 0

10t = 30

t = 3 seconds

In this time, the height is:

y = 30*3 - 5*3^2 = 45 meters

After 5 seconds, the height is:

y = 30*5 - 5*5^2 = 25 meters

The time for the height of 40 meters is:

40 = 30t - 5t^2

t^2 - 6t - 8 = 0

Using Bhaskara's formula, we have:

Delta = 6^2 + 4*8 = 68

sqrt(Delta) = 8.246

t1 = (6 + 8.246) / 2 = 7.123 seconds

t2 = (6 - 8.246) / 2 = -1.123 seconds (negative value for time is not valid)

So the time when the rocket reaches 40 meters is 7.123 seconds

After 7 seconds, the height is:

y = 30*7 - 5*7^2 = -35 meters

The rocket will be 35 meters below the cliff.

5 0
3 years ago
The winning car in a race beat the second car by 19/100 of a second. The third car was 4/10 of a second behind the second car. B
Neko [114]
20/5 should be correct
8 0
3 years ago
Write .33 as a simple form
anyanavicka [17]
.33 in its simplest form is 1/3 I think
3 0
3 years ago
Graph the feasibility region represented by the given inequalities and find the maximum profit if P = 4x + 5y. x ≥ 5 y ≤ 10 2x -
Brilliant_brown [7]

First, graph the three inequalities:  x ≥ 5  ,  y ≤ 10  ,  2x - y  ≤ 8

Next, look for the 3 intersections (vertices) of the lines: (5, 2)  ,  (5, 10)   ,  (9, 10)

Finally, input the vertex coordinates into P = 4x + 5y and look for the biggest #.

(5, 2):  4(5) + 5(2)  = 20 + 10  = 30

(5, 10): 4(5) + 5(10)  = 20 + 50  = 70

(9, 10): 4(9) + 5(10)  = 36 + 50  = 86

Answer: maximum profit = 86


8 0
3 years ago
How does a digit in the ten thousand place compere to a digit in the thousand place
Mademuasel [1]
Ten thousand - 10,000

thousand literally just haves 1,000


if the twenty is before the three zeros, it would be 20,000 which is twenty thousand. its the same with other numbers. its super simple!
7 0
3 years ago
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