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Leya [2.2K]
3 years ago
12

Which fraction is greater 3/4 or 2/3? Find two different ways to show how you know

Mathematics
1 answer:
inessss [21]3 years ago
7 0
3/4 is greater because 3/4=0.75 and 2/3=0.666666666667 and 2/3= 8/12 and 3/4 =9/12
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Paula skates 2 miles in 13 hour. How many miles does she skate in 1 hour?
lilavasa [31]

Answer:

2/13 of an hour

Step-by-step explanation:

3 0
3 years ago
What is the product of (x + 1)/(b2x2 + b2) and b2/(x + 1) expressed in simplest form? A) 1/(x2 + 1) B) x2 + 1 C) b2/(x2 + 1) D)
zhannawk [14.2K]
The answer is A<span>) 1/(x2 + 1) </span>
8 0
4 years ago
If an injectable solution contains 25μg of a dug substance in each 0.5 mL, how many milliliters would be required to provide a p
Kay [80]

Answer:

5mL would be required to provide a patient with 0.25 mg of the drug substance.

Step-by-step explanation:

The problem states that an injectable solution contains 25μg of a dug substance in each 0.5 mL, and asks how many milliliters would be required to provide a patient with 0.25 mg of the drug substance.

So, the first step is the conversion of 25ug to mg, since the problem asks the answer in mg.

Each mg has 1000ug. So

1mg - 1000ug

xmg - 25ug

1000x = 25

x = \frac{25}{1000}

x = 0.025 mg

It means that each 0.5mL of the solution contains 0.025mg of the drug. How many milliliters would be required to provide a patient with 0.25 mg of the drug substance.

0.5mL - 0.025mg

xmL - 0.25mg

0.025x = 0.5*0.25

x = \frac{0.5*0.25}{0.025}

x = 10*0.5

x = 5mL

5mL would be required to provide a patient with 0.25 mg of the drug substance.

6 0
3 years ago
Find the demand function for the marginal revenue function. Recall that if no items are​ sold, the revenue is 0.
Pepsi [2]

The integral that is needed to solve the demand function is R(x) = 599x - 0.14x^{3/2}

<h3>What is Demand Function?</h3>

A demand function describes the mathematical relationship between the quantity demanded and one or more determinants of the demand, as the price of the good or service, the price of complementary and substitute goods, disposable income, etc.

Here, given differential equation;

R'(x) = 599 - 0.21\sqrt{x}

we can also write this as;

\frac{d}{dx}R(x) = 599 - 0.21\sqrt{x}

d R(x) = (599 - 0.21\sqrt{x} ) dx

On integrating both sides, we get

\int\ d R(x) = \int\ (599 - 0.21\sqrt{x} ) dx

R(x) = 599x - 0.21 X \frac{2}{3}x^{3/2} + C

R(x) = 599x - 0.14x^{3/2} + C       ...........(i)

Also given, at x = 0, R(x) = 0, Put these values in equation (i), we get

0 = 0 - 0 + C

C = 0

Put the value of C in equation (i), we get

R(x) = 599x - 0.14x^{3/2}

Thus, the integral that is needed to solve the demand function is R(x) = 599x - 0.14x^{3/2}

Learn more about Demand Function from:

brainly.com/question/20564722

#SPJ1

7 0
2 years ago
For the differential equation dy/dt=ky, k is a constant, y(0)=24, and y(1)=18. What is the value of k?
Gre4nikov [31]

The equation is separable, so solving it is trivial:

\dfrac{\mathrm dy}{\mathrm dt}=ky\implies\dfrac{\mathrm dy}y=k\,\mathrm dt

Integrating both sides gives

\ln|y|=kt+C\implies y=e^{kt+C}=Ce^{kt}

Given y(0)=24 and y(1)=18, we find

24=C

18=Ce^k=24e^k\implies e^k=\dfrac34\implies k=ln\dfrac34

so the answer is E.

8 0
4 years ago
Read 2 more answers
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