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3 years ago

What is a slope of a line passing through the points (5.3) and(7,-2)

Mathematics

2 answers:

nataly862011 [7]3 years ago

8 0

Answer:

The answer is

$- \frac{5}{2} \\$

Step-by-step explanation:

The slope of a line given two points can be found by using the formula

$m = \frac{ y_2 - y _ 1}{x_ 2 - x_ 1} \\$

From the question the points are

(5.3) and(7,-2)

The slope

$m = \frac{ - 2 - 3}{7 - 5} = \frac{ - 5}{2} = - \frac{5}{2} \\$

We have the final answer as

$- \frac{5}{2} \\$

Hope this helps you

Ierofanga [76]3 years ago

6 0

Answer:

-2.5

Step-by-step explanation:

Slope (m) =

ΔY

ΔX

-5

= -2.5

θ =

arctan( ΔY ) + 360°

ΔX

= 291.80140948635°

ΔX = 7 – 5 = 2

ΔY = -2 – 3 = -5

Distance (d) = √ΔX2 + ΔY2 = √29 = 5.3851648071345

Equation of the line:

y = -2.5x + 15.5

y =

- 5 x

+ 31

When x=0, y = 15.5

When y=0, x = 6.2

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3 years ago

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Answer:

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3 years ago

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Marina86 [1]

Answer:

15%

Step-by-step explanation:

His rate is ...

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4 years ago

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kandy is financing a $335,000 mortgage for 30 years at a fixed rate of 7.5% what is the total cost of the principal and interest

-BARSIC- [3]

Given:
<span>F= $335,000
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3 years ago

Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are

Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

$P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}$ .

Recall that $\binom{n}{k}= \frac{n!}{k!(n-k)!}$ In this case, the student passes if X is at least four correct questions, then

$P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696$

c)The expected value of a binomial random variable with parameters n and p is $E[X] = np$ . IN our case, n=6 and p =0.2. Then the expected value of correct answers is $6\cdot 0.2 = 1.2$

5 0

4 years ago