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3 years ago

13

CAN SOMEONE HELP ME WITH THIS PLEASE ??

1 answer:

masya89 [10]3 years ago

3 0

Remark
The very first thing you should do is graph the function, which I have done. It is at the bottom of this answer.

Step One
Where is the hole and what kind is it? This graph has a hole at x = 2. At that point the function is 0/0. A hole is defined as the point created by a zero in one of the factors that is the same in the numerator and denominator. Both = 0.

Step 2
Find the vertical asymptote.
That occurs when denominator alone has a factor that is = 0. In this case when x = 3 the whole equation blows up (or down) and you have a vertical asymptote. The graph is discontinuous at this point.

Step three
Find the horizontal Asymptote.
Horizontal assymptotes occur when (in this case) the power of the factors in the denominator exceeds the power of the factors in the numerator. In this case that is true and the horizontal assymptote occurs around the line y = 0.

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Emily is 4 times as old as Tiffany. In ten years time, Emily will be twice as old as Tiffany . Find their ages.

Sholpan [36]

<h3><u>Question</u><u>:</u></h3>

Emily is 4 times as old as Tiffany. In ten years time, Emily will be twice as old as Tiffany. Find their ages.

<h3><u>Solution</u><u>:</u></h3>

Let the age of Tiffany be x years.
Then, the age of Emily = 4x years.
After 10 years, the age of Tiffany will be (x+10) years.
After 10 years, the age of Emily will be (4x+10) years.
Therefore, by the problem

$4x + 10 = 2(x + 10) \\ = 4x + 10 = 2x + 20 \\ = > 4x - 2x = 20 - 10 \\ = > 2x = 10 \\ = > x = \frac{10}{2} \\ = > x = 5$

So, Tiffany's present age = 5 years.
Emily's present age = (4×5) years = 20 years.

<h3><u>Answer:</u></h3>

Emily's age is 20 years and Tiffany's age is 5 years.

Hope it helps!

7 0

2 years ago

Read 2 more answers

Find the difference <br> 5 2/3 - 3 1/5 <br> A. 5 2/3<br> B. 8 13/15<br> C. 2 7/15<br> D. 3 1/5

RSB [31]

To find the difference of given expression:

$5\frac{2}{3} -3\frac{1}{5}$

First step is to subtract the whole number5 and 3.

So, 5 - 3 = 2.

Now we can find the difference of fractions.

To subtract the fractions , we need to find the common denominator.

Common denominator of 3 and 5 is 15.

So, we need to make both the denominator equal to 15.

$\frac{2}{3} =\frac{2*5}{3*5} =\frac{10}{15}$

Similarly, $\frac{1}{5} =\frac{1*3}{3*5} = \frac{3}{15}$

Therefore, $\frac{2}{3} -\frac{1}{5} =\frac{10}{15} -\frac{3}{15}$

= $\frac{10-3}{15}$

= $\frac{7}{15}$

So, the difference of given expression is $2\frac{7}{15}$ .

So, the correct choice is C.

3 0

2 years ago

If m and n are the zeroes of the polynomial 6y 2 -7y – 2, find a polynomial whose zeroes are 1/m and 1/n

denis-greek [22]

Answer:

$y^2-\frac{7}{2}y+3$

Step-by-step explanation:

Given polynomial is,

6y² - 7y - 2

Fro the zeros of the given polynomial,

6y² - 7y - 2 = 0

6y² - 4y - 3y - 2 = 0

2y(3y - 2) - 1(3y - 2) = 0

(2y - 1)(3y - 2) = 0

(2y - 1) = 0

y = $\frac{1}{2}$

(3y - 2) = 0

y = $\frac{2}{3}$

Therefore, zeros of this polynomial are m = $\frac{1}{2}$ and n = $\frac{2}{3}$

If a polynomial has zeros as $\frac{1}{m}$ and $\frac{1}{n}$ then the zeros will be $\frac{3}{2}$ and 2.

Polynomial will be,

$(y-\frac{3}{2})(y-2)$

= $y(y-2)-\frac{3}{2}(y-2)$

= $y^2-2y-\frac{3}{2}y+3$

= $y^2-\frac{7}{2}y+3$

7 0

2 years ago

What is the answer to 498/7 long division

-BARSIC- [3]

I hope this helped! Mark me Brainliest! :) -Raven❤️

3 0

2 years ago

Find the extrema of the function y=cos2x

marishachu [46]

Answer:

Step-by-step explanation:

Find derivative of the function:

y' = -2·sin(2·x)

-2·sin(2·x) = 0

x1 = 0

x2 = 3.142

f(0) = 1

f(3.142) = 1

Answer

fmin = 1, fmax = 1

4 0

2 years ago