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antoniya [11.8K]
3 years ago
5

Which scatterplot has a correlation coefficient closest to r= 1?

Mathematics
2 answers:
worty [1.4K]3 years ago
5 0

Answer:

the first graph

Step-by-step explanation:

Ksju [112]3 years ago
4 0

Answer:

-1

Step-by-step explanation:

in statistics, the correlation coefficient r measures the strength and direction of a linear relationship between two variables on a scatterplot. The value of r is always between +1 and –1. To interpret its value, see which of the following values your correlation r is closest to: Exactly –1.

hope this help

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What’s the answer to this thank u for ur help:)
goldfiish [28.3K]

Answer:

b. DAC≅DBC

Step-by-step explanation:

∠DCB≅∠DCA=90° as they are right angles at the perpendicular lines

DC=DC reflexive property(they are the same line)

AC=CB they are both the radius of the same circle

DAC≅DBC   due to SAS(Side angle Side)

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3 years ago
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Use the information frompart a to write an equation representing the number of colories burned each minute while bowling. Let m
Fofino [41]

Answer:

To find the number of calories burned:

Find the Metabolic Equivalent of Task (MET) value of the task.

Calculate the number of calories burned per minute. (MET x body weight in kg x 3.5) / 200.

Multiply the calories burned per minute by the number of minutes of activity.

Now, as per the question, weight is 125 pounds (lb), we will convert the weight in kilogram (kg) which is 1 lb = 0.453 kg, it means 125 lb = 56.7

Now we have to find the MET,

A metabolic equivalent (MET) value is a measurement of the energy cost of a specific physical activity for a specific period of time.

For example. A MET of 1 would be roughly equivalent to a person's energy expenditure from sitting still in a room temperature and not actively digesting food.

As per the Calorie guide value of MET for bowling is 3.9

Now the overall formula is

Calorie Burn (x) = ((MET * body weight in kg * 3.5) / 200) * (Number of minutes) m

x = ((3.9*56.7*3.5)/200) * m

Finally, x = 3.87 m represents the number of calorie burned (x) while bowling m minutes.

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3 years ago
f the dean wanted to estimate the proportion of all students receiving financial aid to within 3% with 99% reliability, how many
Oksanka [162]

Answer:

n=1849

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Assuming that the proportion is estimated \hat p =0.5. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.03}{2.58})^2}=1849  

And rounded up we have that n=1849

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