make a probability tree it will really help so much
The turtle that would most likely win the race is the turtle 7
<h3>How to determine the turtle with the most chance?</h3>
The turtles are given as:
Turtle = 1 to 13
When two dice are rolled and the sum of the outcomes are taken, the sample space is:
<u>Outcome Frequency</u>
2 1
3 2
4 3
5 4
6 5
7 6
8 5
9 4
10 3
11 2
12 1
The outcome 7 has the highest frequency of 6
This means that the turtle 7 has the highest chance of winning the race
Read more about probability at:
brainly.com/question/25870256
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Answer:
Two-tailed test.
Step-by-step explanation:
There are two types of tests:
One-tailed tests and two-tailed tests.
When we only test if the mean is less or more than a value, we have a one-tailed test.
When we test if the mean is different from a value, we have a two-tailed test.
If you were to conduct a test to determine whether there is evidence that the proportion is different from 0.30, which test would you use?
Test if it is different, so a two-tailed test.
To solve this question, I first converted one hour into minutes. (60 minutes)
Then I divided 4 1/2 into 60. As a decimal, the answer if 0.075. If you convert that into a lowest terms fraction, you get 3/40.
We are going to denote the number of additional minutes with

, and the total cost of the call with

.
From PONCO, we know that they charge $1.25 for the first minute, and $0.30 for each additional minute; knowing that our additional minute is

and our total cost of the call is

, we can set up an equation to relate the values:

we are going to call this equation (1)
From CowBell, we know that they charge 1.40 for the first minute, and $0.25 for each additional minute. so just like before we can set up an equation to relate the values:

We are going to call this equation (2)
Since the total cost

of equations (1) and (2) is the same, we can equate them to find

:




We can conclude that after 3 additional minutes the cost of the calls will be the same; therefore, the correct answer is
B.