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3 years ago

Which scatterplot has a correlation coefficient closest to r= 1?

Mathematics

2 answers:

worty [1.4K]3 years ago

5 0

Answer:

the first graph

Step-by-step explanation:

Ksju [112]3 years ago

4 0

Answer:

-1

Step-by-step explanation:

in statistics, the correlation coefficient r measures the strength and direction of a linear relationship between two variables on a scatterplot. The value of r is always between +1 and –1. To interpret its value, see which of the following values your correlation r is closest to: Exactly –1.

hope this help

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How many 1/4 cup servings of raisins are in 3/8 cup of raisins?

MissTica

namely, how many times does 1/4 go into 3/8?

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3 years ago

Read 2 more answers

An aircraft seam requires 22 rivets. The seam will have to be reworked if any of these rivets is defective. Suppose rivets are d

SpyIntel [72]

Answer:

Part A:

$p=0.0095$

Part B:

$p=0.0043$

Step-by-step explanation:

Part A:

The number of rivets=22 rivets

Probability that no rivet is defective= (1-p)^22

The probability that at least one rivet is defective=1-(1-p)^22

For 19% of all seams need reworking, probability that a rivet is defective is given by:

$1-(1-p)^{22}=0.19$

$(1-p)^{22}=0.81\\p=1-\sqrt[22]{0.81} \\p=0.0095$

Part B:

For 9% of all seams need reworking, probability of a defective rivet is:

$1-(1-p)^{22}=0.09\\p=1-\sqrt[22]{0.91} \\p=0.0043$

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3 years ago

Solve 0.21 x 2 = ________. Use the model to help you find the product. (1 point)

Nadusha1986 [10]

Answer:

0.42

Step-by-step explanation:

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3 years ago

Find the fourth roots of 81(cos 320° + i sin 320° ). Write the answer in trigonometric form.

Liono4ka [1.6K]

Using the De Moivre's Theorem, let us work out for the fourth roots of 81(cos 320° + i sin 320° ).

zⁿ = rⁿ (cos nθ + i sin nθ)
z⁴ = 81(cos 320° + i sin 320° )
z = ∜[81(cos 320° + i sin 320° )]
= ∜[3^4 (cos 4*80° + i sin 4*80°)]
= 3(cos 80° + i sin 80°)

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3 years ago

Read 2 more answers

5y+1=1<br> Subtract 1 from both sides

maks197457 [2]

Step-by-step explanation:

$5y + 1 = 1 \\ subtracting \: 1 \: from \: both \: sides \\ \red{ \boxed{ \bold{ 5y + 1 - 1 = 1 - 1}}} \\ 5y = 0 \\ y = 0$

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3 years ago