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Ne4ueva [31]
3 years ago
14

Jason alleges that if the means and mean absolute deviation of two different lists of numbers are the same, then all of the numb

ers in the two lists are the same. Is Jason correct? explain your answer.
Mathematics
1 answer:
olga55 [171]3 years ago
3 0
Yes he is correct................................................................................................................................................................
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The volume of a right triangular prism is 72 cubic feet. The height of the prism is 9 feet. The triangular base is an isosceles
Mariulka [41]

Answer:

Step-by-step explanation:

volume = area of base * height = area of base * 9 = 72

-> area of base = 72/9 = 8

let a,b,c be the length of sides of isosceles right triangle base

we have a = b and a*b/2 = 8 ft2

-> a*a/2 = 8ft2

-> a*a = 16

-> a=4ft=b

have c^2 = a^2 + b^2 = 16 +16 = 32

-> c = \sqrt{32} = 5.656 ft

Since i dont know that is DF, i calculate both a,b and c

3 0
3 years ago
Read 2 more answers
Can you simplify 14x+11 please??
ad-work [718]

Answer:

It cannot be further simplified

Step-by-step explanation:

11 is a prime number, so there are no numbers that can go into 14 and 11 (besides 1 and 1 would not simplify the problem)

6 0
3 years ago
.A variety of stores offer loyalty programs. Participating shoppers swipe a bar-coded tag at the register when checking out and
Leni [432]

Answer:

a) Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

b) t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

The degrees of freedom are given by:

df = n-1 = 80-1=79

The p value for this case taking in count the alternative hypothesis would be:

p_v =P(t_{79}>2.236)=0.0141  

Step-by-step explanation:

Information given

\bar X=130 represent the sample mean for the amount spent each shopper

s=40 represent the sample standard deviation

n=80 sample size  

\mu_o =120 represent the value to verify

t would represent the statistic    

p_v represent the p value f

Part a

We want to verify if the shoppers participating in the loyalty program spent more on average than typical shoppers, the system of hypothesis would be:  

Null hypothesis:\mu \leq 120  

Alternative hypothesis:\mu > 120  

The statistic for this case would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Replacing the info given we got:

t=\frac{130-120}{\frac{40}{\sqrt{80}}}=2.236  

The degrees of freedom are given by:

df = n-1 = 80-1=79

The p value for this case taking in count the alternative hypothesis would be:

p_v =P(t_{79}>2.236)=0.0141  

5 0
3 years ago
Corrected work and description of error
hichkok12 [17]

Answer:

hmm i have no idea can u send a clear pic of question?

8 0
2 years ago
Solve for X: 3-2(x-1)=x-10
lyudmila [28]
3-2(x-1)=x-10 \\\\ 3-2x+2=x-10 \\\\ -2x+5=x-10 \\\\ -2x-x=-10-5 \\\\ -3x=-15 \\\\ \boxed{x=\frac{-15}{-3}=5}
6 0
3 years ago
Read 2 more answers
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