All categories

4 years ago

What is the equation of a line that passes through (7, 8) and has a slope of -3?

Mathematics

1 answer:

Luda [366]4 years ago

5 0

Using point-slope form,
(y-8)= 7(x-8)

y = 7x - 56 + 8
y = 7x -48
0r
7x -y = 48

You might be interested in

What si the meaning of 3:4

garik1379 [7]

Answer:

3:4 is a ratio

Step-by-step explanation:

so every 3 cats their are 4 dogs ect

3 0

4 years ago

Read 2 more answers

Each of the letters of the word ALABAMA are written on a piece of paper and then

Kruka [31]

Answer:

3/7

Step-by-step explanation:

There are 7 letters in ALABAMA. And there are 4 A's in ALABAMA. So if you're trying to not get an A then you would subtract 4 from 7. Which you would get 3/7 of the letters in ALABAMA are not A.

7 0

3 years ago

If m∠4 = (5x+4)° and m∠6 = (7x-36)°, then x = ______.

gizmo_the_mogwai [7]

Answer:

x=20

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

How do I know when to add or subtract when solving translations problem

andreyandreev [35.5K]

Answer: Look for key words.

Step-by-step explanation:

Example: 15 added and 24.

Added is the key word

24 + 15

7 0

4 years ago

Read 2 more answers

Find a parametric representation for the part of the cylinder y2 + z2 = 49 that lies between the planes x = 0 and x = 1. x = u y

sweet-ann [11.9K]

Answer:

The equation for z for the parametric representation is $z = 7 \sin (v)$ and the interval for u is $0\le u\le 1$ .

Step-by-step explanation:

You have the full question but due lack of spacing it looks incomplete, thus the full question with spacing is:

Find a parametric representation for the part of the cylinder $y^2+z^2 = 49$ , that lies between the places x = 0 and x = 1.

$x=u\\ y= 7 \cos(v)\\z=? \\ 0\le v\le 2\pi \\ ?\le u\le ?$

Thus the goal of the exercise is to complete the parameterization and find the equation for z and complete the interval for u

Interval for u

Since x goes from 0 to 1, and if x = u, we can write the interval as

$0\le u\le 1$

Equation for z.

Replacing the given equation for the parameterization $y = 7 \cos(v)$ on the given equation for the cylinder give us

$(7 \cos(v))^2 +z^2 = 49 \\ 49 \cos^2 (v)+z^2 = 49$

Solving for z, by moving $49 \cos^2 (v)$ to the other side

$z^2 = 49-49 \cos^2 (v)$

Factoring

$z^2 = 49(1- \cos^2 (v))$

So then we can apply Pythagorean Theorem:

$\sin^2(v)+\cos^2(v) =1$

And solving for sine from the theorem.

$\sin^2(v) = 1-\cos^2(v)$

Thus replacing on the exercise we get

$z^2 = 49\sin^2 (v)$

So we can take the square root of both sides and we get

$z = 7 \sin (v)$

4 0

3 years ago