All categories

2 years ago

Choose the like terms: 3h, i, 4i is it i and 4i

2 answers:

soldier1979 [14.2K]2 years ago

7 0

Options are: 3h, i, 4i.

The options that have in common are second and third because each of them has i. That means that what you think is correct.
the answer is 4i and i

GaryK [48]2 years ago

5 0

I think it is 4i and i cause they r like terms.

You might be interested in

What does y equal in this problem 5y-3(2-y)=10

Pepsi [2]

Steps:

5y - 6 + 3y = 10

8y = 10 + 6

y = 16/8

y = 2

Hope this helps! :)

3 0

3 years ago

If 8 is subtracted from 7 times a number the result is 34

djverab [1.8K]

7x - 8 = 34

Solving:

7x = 34 + 8
7x = 42
x = 6

Hope this helps!

5 0

3 years ago

Few students manage to complete their schooling without taking a standardized admissions test such as the Scholastic Achievement

slega [8]

Answer:

Step-by-step explanation:

Assuming there is a punitive removal of one point for an incorrect response.

Five undiscernable choices: 20% chance of guessing correctly -- Expectation: 0.20*(1) + 0.80*(-1) = -0.60

Four undiscernable choices: 25% chance of guessing correctly -- Expectation: 0.25*(1) + 0.75*(-1) = -0.50

I'll use 0.33 as an approzimation for 1/3

Three undiscernable choices: 33% chance of guessing correctly -- Expectation: 0.33*(1) + 0.67*(-1) = -0.33 <== The approximation is a little ugly.

Two undiscernable choices: 50% chance of guessing correctly -- Expectation: 0.50*(1) + 0.50*(-1) = 0.00

And thus we see that only if you can remove three is guessing neutral. There is no time when guessing is advantageous.

One Correct Answer: 100% chance of guessing correctly -- Expectation: 1.00*(1) + 0.00*(-1) = 1.00

6 0

3 years ago

Solve the equation pls <br> 4t=32

iren [92.7K]

The answer is 6. Because 4x6=32

8 0

3 years ago

Read 2 more answers

A genetics experiment involves a population of fruit flies consisting of 1 male named Bart and 3 females named Charlene, Diana,

kenny6666 [7]

Answer:

(b) $\frac{1}{2}$

Step-by-step explanation:

1 male named Bart (b)

3 females named Charlene(c), Diana(d), and Erin(e).

Since there is replacement, the possible samples are:

bb, bc, be, bd, cb, cc, cd, ce, db, dc, dd, de, eb, ec, ed, and ee.

Total Number of pairs = 16

Event of picking 2 males:bb

Event of 1 male:bc,cb,bd,db,be,eb

Event of picking 0 males:

cc, cd, ce, dc, dd, de, ec, ed, and ee.

$\begin{equation*} \begin{matrix}Proportion of males & Probability \\0 & 9/16 \\1 & 6/16 \\2 & 1/16 \end{matrix} \end{equation*}$

b. The mean of the sampling distribution

$\mu = (\frac{9}{16} X0 ) +(\frac{6}{16} X 1)+(\frac{1}{16} X 2) = \frac{8}{16} = \frac{1}{2}$

c. No; the proportion of males is $\frac{1}{4}$ while the mean is $\frac{1}{2}$ .

B. No, the sample mean is not equal to the population proportion of males. These values are not always equal, because proportion is an unbiased estimator.

7 0

3 years ago