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3 years ago

Choose the like terms: 3h, i, 4i is it i and 4i

2 answers:

soldier1979 [14.2K]3 years ago

7 0

Options are: 3h, i, 4i.

The options that have in common are second and third because each of them has i. That means that what you think is correct.
the answer is 4i and i

GaryK [48]3 years ago

5 0

I think it is 4i and i cause they r like terms.

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How do you solve -10 = 8 + v

babunello [35]

Answer: -18=v

Step-by-step explanation: You subtract 8 from both sides. -10-8=-18 which will equal to v.

6 0

3 years ago

Read 2 more answers

15. In the drawing, find the perimeter of triangle BIS.<br>

Nesterboy [21]

Answer:

29.86 units

Step-by-step explanation:

In the triangle BIS, IT is the bisector of angle BIS,

$BI \cong ST.... (given) \\$

Let BI = ST = x... (1)

By angle bisector property of a triangle, we have:

$\frac{BI}{IS} = \frac{BT}{ST}.... (2)\\\\\frac{x}{12} = \frac{4}{x}\\\\x\times x = 12\times 4\\\\x^2 = 48\\\\x=\sqrt{48}\\\\x = 6.92820323\\\\x = 6.93\\$

Therefore,

BI = ST =6.93

Perimeter of triangle BIS

= BI + IS + ST + BT

= 6.93 + 12 + 6.93 + 4

= 29.86 units

3 0

3 years ago

Which of the following is equivalent to the expression below for x≠6?

nata0808 [166]

Answer:

The fourth answer choice is the correct one: 2(x - 3)

Step-by-step explanation:

2x²-18x+36/x-6 should be factored, as follows:

2(x²-9x+18) / (x-6) = 2(x - 3) (x - 6) / (x - 6)

Substituting x = 6 would result in division by zero and is thus not allowed.

Remembering this, we can reduce 2(x - 3) (x - 6) / (x - 6) to 2(x - 3) for x≠6.

6 0

3 years ago

A mug and its dimensions are shown. Ben pours hot cocoa into the mug, leaving 0.5 inches empty at the top. Using 3.14 for s, abo

Evgesh-ka [11]

Answer:

Step-by-step explanation:

radius: diameter/2 = 3 /2 = 1.5 in

new height = 3.5 - 0.5 = 3 in

V = radius^2 x 3.14 x height = 1.5^2 x 3.14 x 3 = 21.2 in^3

8 0

3 years ago

Find two unit vectors orthogonal to both given vectors. i j k, 4i k

Maurinko [17]

The cross product of two vectors gives a third vector $\mathbf v$ that is orthogonal to the first two.

$\mathbf v=(\vec i+\vec j+\vec k)\times(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\\1&1&1\\4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k$

Normalize this vector by dividing it by its norm:

$\dfrac{\mathbf v}{\|\mathbf v\|}=\dfrac{\vec i+3\,\vec j-4\,\vec k}{\sqrt{1^2+3^2+(-4)^2}}=\dfrac1{\sqrt{26}}(\vec i+3\,\vec j-4\vec k)$

To get another vector orthogonal to the first two, you can just change the sign and use $-\mathbf v$ .

6 0

3 years ago