Answer:
a. y = 2+4.3x when x = -6
substituting value of x, we get
<u>y=2+4.3*-6=2-25.8=23.8</u>
b. y = (x-3)² when x = 9
substituting value of x, we get
<u>y</u><u>=</u><u>(</u><u>9</u><u>-</u><u>3</u><u>)</u><u>²</u><u>=</u><u>6</u><u>²</u><u>=</u><u>3</u><u>6</u>
c. y=x-2 when x = 3.5
substituting value of x, we get
<u>y</u><u>=</u><u>3</u><u>.</u><u>5</u><u>-</u><u>2</u><u>=</u><u>1</u><u>.</u><u>2</u>
d. y=5x-4 when x = - 2
substituting value of x, we get
<u>y</u><u>=</u><u>5</u><u>*</u><u>-</u><u>2</u><u>-</u><u>4</u><u>=</u><u>-</u><u>1</u><u>0</u><u>-</u><u>4</u><u>=</u><u>-</u><u>1</u><u>4</u>
Answer :
<u>A the triangle is not a right </u><u>triangle</u>
<u>D </u><u>costheta</u><u> </u><u><0</u>
The law of cosines says:
a²=b²+c²−2bccos(θ)
Rewriting:
2bccos(θ)=b²+c²−a²<0
So cos(θ)<0cos(θ)<0 since 2bc>02bc>0. Since 0<θ<π0<θ<π in any triangle,
π/2<θ<π
So:
1. θ is not an acute angle.
2 The triangle is not a right triangle. In a right triangle, one of the angles is 90 degrees and the other two are then less than 90 degrees. This triangle has an angle greater than 90 degrees.
3. cos(θ)<0 is true.
4. cos(θ)>0 is false -3 says cos(θ) is negative; a number can't be both positive and negative.
Answers:
First box: 3Pi/4
Second box: 4Pi/3
Third box: Pi/2
Fourth box: 3Pi/2
Please, see the attached files.
Thanks.
Answer: x = -10
Step-by-step explanation:
x +4=-6
x = - 6 - 4
x = -10
