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3 years ago

In a chemical reaction, how is energy involved in breaking and in making chemical bonds?

1 answer:

8 0

I chemical reaction how energy involves in breaking chemical bonds well first off you have to get carbon dioxide plus Carmen dioxide equals air right well that’s wrong carbon dioxide equals Nancy Pelosi equals such a tourist mall

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Which of the following changes will always be true for a spontaneous reaction?

avanturin [10]

It will be negative delta G

6 0

3 years ago

Read 2 more answers

Given the balanced ionic equation representing the reaction in an operating voltaic cell: zn(s) + cu2+(aq) → zn2+(aq) + cu(s) th

soldi70 [24.7K]

Answer: from the Zn anode to the Cu cathode

Justification:

1) The reaction given is: Zn(s) + Cu₂⁺ (aq) -> Zn²⁺ (aq) +Cu(s)

2) From that, you can see the Zn(s) is losing electrons, since it is being oxidized (from 0 to 2⁺), while Cu²⁺, is gaining electrons, since it is being reduced (from 2⁺ to 0).

3) Then, you can already tell that electrons go from Zn to Cu.

4) The plate where oxidation occurs is called anode, and the plate where reduction occus is called cathode.

So you get that the electrons flow from the anode (Zn) to the cathode (Cu).

Always oxidation occurs at the anode, and reduction occurs at the cathode.

3 0

4 years ago

The solubility of lead(II) iodide is 0.064 g/100 mL at 20ºC. What is the solubility product for lead(II) iodide?

quester [9]

Answer:

$Ksp=1.07x10^{-8}$

Explanation:

Hello,

In this case, the dissociation reaction is:

$PbI_2(s)\rightleftharpoons Pb^{2+}(aq)+2I^-(aq)$

For which the equilibrium expression is:

$Ksp=[Pb^{2+}][I^-]^2$

Thus, since the saturated solution is 0.064g/100 mL at 20 °C we need to compute the molar solubility by using its molar mass (461.2 g/mol)

$Molar solubility=\frac{0.064g}{100mL}*\frac{1000mL}{1L}*\frac{1mol}{461.2g}=1.39x10^{-3}M$

In such a way, since the mole ratio between lead (II) iodide to lead (II) and iodide ions is 1:1 and 1:2 respectively, the concentration of each ion turns out:

$[Pb^{2+}]=1.39x10^{-3}M$

$[I^-]=1.39x10^{-3}M*2=2.78x10^{-3}M$

Thereby, the solubility product results:

$Ksp=(1.39x10^{-3}M)(2.78x10^{-3}M)^2\\\\Ksp=1.07x10^{-8}$

Regards.

6 0

4 years ago

Sub-groups on periodic table

marissa [1.9K]

Answer:

Subgroups S, P, D, F, including elements of blocks s, p, d, f, respectively.

<h2>Hope it helps you✨. </h2>

Thanks☸.

4 0

3 years ago

Provide the most likely dominant bonding mechanism in the following solid compounds:a.CaO b. InAs c. Al2O3 d.Bronze

padilas [110]

Answer:

CaO- ionic

InAs-covalent

Al2O3-ionic

Bronze- metallic

Explanation:

CaO and Al2O3 are mostly ionic even though the posses a little covalent character but ionic bonding is the main bonding scheme. Bronze is an alloy of two metals hence it contains a metallic bond. InAs has an electro negativity difference of 0.4 between the atoms so it is a polar covalent bond.

5 0

4 years ago

In a chemical reaction, how is energy involved in breaking and in making chemical bonds?​

In a chemical reaction, how is energy involved in breaking and in making chemical bonds?