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katen-ka-za [31]
3 years ago
13

In a chemical reaction, how is energy involved in breaking and in making chemical bonds?​

Chemistry
1 answer:
alexira [117]3 years ago
8 0
I chemical reaction how energy involves in breaking chemical bonds well first off you have to get carbon dioxide plus Carmen dioxide equals air right well that’s wrong carbon dioxide equals Nancy Pelosi equals such a tourist mall
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Which phrase describes the energy of collision?(1 point)
Kruka [31]

The phrase that describes the energy of collision is D. kinetic energy transferred when billiard balls hit each other.

<h3>What is collision?</h3>

collision can be regarded as  coming together of one solid or direct impact to the other such as car collided with a tree.

Therefore, kinetic energy transferred when billiard balls hit each other is an example.

Learn more about collision at;

brainly.com/question/11352260

8 0
3 years ago
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What Is A Sublimation
kondaur [170]

Answer:

sublimation is the transition of a substance directly from the solid  to the gas phase without passing throught the intermedate liquid phase

such as the following

dry ice

air fresheners

freese drying

moth balls

Explanation:

5 0
3 years ago
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At 298 K the standard enthalpy of combustion of sucrose is -5645 kJ/mol and the standard reaction Gibbs energy is -5798 kJ/mol.
natka813 [3]

Explanation:

The given data is as follows.

             T = 298 K,          \Delta H^{o} = -5645 kJ/mol

          \Delta G^{o} = -5798 kJ/mol

Relation between \Delta H and \Delta G are as follows.

          \Delta G^{o} = \Delta H^{o} - T \Delta S^{o}    

             -5798 kJ/mol = -5645 kJ/mol - 298 \times \Delta S^{o}

                       -153 kJ/mol = -298 \times \Delta S^{o}

                    \Delta S^{o} = 0.513 kJ/mol K

Now, temperature is 37^{o}C = (37 + 273) K = 310 K

Since,        \Delta G = \Delta H^{o} - T \Delta S^{o}

                            = -5645 kJ/mol - 310 K \times 0.513 kJ/mol K

                            = (-5645 kJ/mol - 159.03 kJ/mol)

                            = -5804.03 kJ/mol

As, change in Gibb's free energy = maximum non-expansion work

            \Delta G = \Delta G_{310 K} - \Delta G_{298 K}

                           = -5804.03 kJ/mol - (-5798 kJ/mol)

                           = -6.03 kJ/mol

Therefore, we can conclude that the additional non-expansion work is -6.03 kJ/mol.

5 0
3 years ago
Which of the following is an example of acceleration?
Dahasolnce [82]

Answer:

A car speeds up from 0 km/hr to 100 km/hr in 6 seconds.

Explanation:

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How do scientists use radioactive decay to date fossils and artifacts
RideAnS [48]
The level of radioactivity allows them to date fossils and artifacts
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