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3 years ago

How do electrons populate atoms?

1 answer:

7 0

Electrons fill the electron orbitals (s, p, d, or f) starting from the lowest energy level going to the highest energy level. I hope this helps. let me know if you need more information such as what the

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How many atoms are in 12 moles of silver?

lord [1]

Answer:

NA=72.264x1023

Explanation:

I got you

7 0

3 years ago

- Write down Rutherford's atomic model with diagram .also write down defects of Rutherford's atomic model. - write down neil boh

anastassius [24]

this is the answer

sorry if the answer is wrong

5 0

3 years ago

Mason notices that his boat sinks lower in the water in a freshwater lake than in the ocean. what could explain this

tino4ka555 [31]

Answer:

Mason notices that his boat sinks lower into the water in a freshwater lake than in the ocean. What could explain this?

Explanation:

The freshwater has less density then the ocean!

6 0

3 years ago

5.58e-18 + 8.65e-13 / -8.76e+06

evablogger [386]

Answer:

this is the answer:

− 10.13099839

Explanation:

5 0

3 years ago

What expression approximates the volume of O2 consumed, measure at STP, when 55 g of Al reacts completely with excess O2?2 Al(s)

Genrish500 [490]

Answer:

34.28 L ( 1.5*22.4 L)

Explanation:

Calculation of the moles of aluminum as:-

Mass = 55 g

Molar mass of aluminum = 26.981539 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{55\ g}{26.981539\ g/mol}$

$Moles= 2.0384\ mol$

According to the reaction:-

$4Al+3O_2\rightarrow 2Al_2O_3$

4 moles of aluminum react with 3 moles of oxygen gas

1 mole of aluminum react with $\frac{3}{4}$ moles of oxygen gas

2.0384 moles of aluminum react with $\frac{3}{4}\times 2.0384$ moles of oxygen gas

Moles of oxygen gas = 1.5288 moles

At STP,

Pressure = 1 atm

Temperature = 273.15 K

Using ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

1 atm × V = 1.5288 mol × 0.0821 L.atm/K.mol × 273.15 K

⇒V = 34.28 L ( 1.5*22.4 L)

7 0

3 years ago