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stiks02 [169]
3 years ago
5

The problem is in the picture. Please help. I am reviewing for the SAT.

Mathematics
2 answers:
Bad White [126]3 years ago
8 0

Answer:

  5

Step-by-step explanation:

The solutions are the solutions to the two equations ...

  • -5 = 2x +1   ⇒   x = -3
  • 5 = 2x +1   ⇒   x = 2

The difference between the solutions is 5.

_____

If you consider what the absolute value is doing, it is telling you twice the difference between x and -1/2 is 5:

  |2(x -(-1/2)}| = 5

  |x -(-1/2)| = 5/2

The solutions to this will be points on the number line that are 5/2 units either side of -1/2, so they will be 5 units apart.

Effectively, the answer to the question is 2(5/2) = 5, where 5 is the number on the right of the equation, and the 2 in the denominator is the coefficient of x.

The 2 in the numerator comes from the solutions being separated by twice the distance either solution is from x=-1/2.

Ludmilka [50]3 years ago
5 0

The absolute value of a quantity is 5 if that quantity is either 5 or -5.

So, the two solutions are

2x+1=5 \iff 2x=4 \iff x=2

2x+1=-5 \iff 2x=-6 \iff x=-3

Now, there is a bit of ambiguity here: we are not told who a and b are exactly, and yet the value of a-b depends on our choice.

If we choose a = 2 and b = -3, then the value of a-b is 5

If we choose a = -3 and b = 2, then the value of a-b is -5

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A train leaves Philadelphia at 2:00 PM. A second train leaves the same city in the same direction at 4:00 PM. The second train t
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Answer: First train speed shall be 42 mi/hr

Second train speed shall be 84 mi/hr

Yes it is the valid answer, it gets annoying when almost everyone enters the wrong answer for a good laugh. Either way, hope this helps! Have a spectacular day.

Step-by-step explanation:

What is the 1st train's head start in miles?

Let +s+ = the speed of the 1st train in mi/hr

From 2PM to 4PM is 2 hrs

+d%5B1%5D+=+s%2A2+

---------------------

Let +d+ = distance the 2nd train travels until

it overtakes the 1st train

From 4PM to 6PM is 2 hrs

Start time when the 2nd train leaves

---------------------

Equation for 1st train:

(1) +d+-+2s+=+s%2A2+

Equation for 2nd train:

(2) +d+=+%28+s%2B42+%29%2A2+

--------------------

Substitute (2) into (1)

(1) +%28+s%2B42+%29%2A2+-+2s+=+s%2A2+

(1) +2s+%2B+84+-+2s+=+2s+

(1) +2s+=+84+

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and

+s%2B+42+=+42+%2B+42+

+s+%2B+42+=+84+

------------------

The 1st train's speed is 42 mi/hr

The 2nd train's speed is 84 mi/hr

---------------------------

check:

(2) +d+=+%28+s%2B42+%29%2A2+

(2) +d+=84%2A2+

(2) +d+=+168+

and

(1) +d+-+2s+=+s%2A2+

(1) +d+-+2%2A42+=+42%2A2+

(1) +d+=+84+%2B+84+

(1) +d+=+168+

8 0
2 years ago
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