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shutvik [7]
3 years ago
9

PLEASE SOLVE IM IN A TEST!

Mathematics
1 answer:
guajiro [1.7K]3 years ago
3 0

Answer:

just guess c its mostly right

Step-by-step explanation:

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Given the equation Square root of 8x plus 1 = 5, solve for x and identify if it is an extraneous solution.
Kisachek [45]
Do recall that squaring and the *radical sign* cancel each other out... like so:(\sqrt{a})^{2}= a

When you put it that way, it isn't enough :P
(\sqrt{a})^{2}= a
(\sqrt{8x+1})^{2}=?

so you start with
(\sqrt{8x+1})^{2}= (5)^{2}
8x+1=25 <-- subtract 1 to both sides
8x=24 <- divide 8 to both sides
x= 3

To find out if it's an extraneous solution ask yourself: It mustn't result in a radical that I like to call... 'illegal'. Plug it into the radicand 8x+1 and make sure you get something that is not a negative number.... so, DO you get a negative number when you plug in x = 3 into the radicand?

(extraneous solution is a invalid solution)

x=3 not extraneous


6 0
3 years ago
Read 2 more answers
Which of these systems of equations has one solution?
vodomira [7]

Answer: B

Step-by-step explanation:

8 0
2 years ago
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Kolby decided he wanted to go to the amusement park. The amusement park charges $8.00 for entry and $1.40 for each ride.
Dmitry_Shevchenko [17]

Answer:

Part A:

1.40x+8.00=C

Part B:

1.40x+8=26

        -8   -8

1.40x=18

/1.40    /1.40

x=11 total rides

Step-by-step explanation:

An expression to represent this would be 1.40x+8.00=C (C is total cost).

If you had $26.00 you would first spend $8.00 on the entry leaving you with $18.00. Then you would divide the $18 by $1.40 for each ride to get 12.8... It doesn't make sense to go on a fraction of a ride so you just round down to 11 rides

8 0
2 years ago
The points A (4, 0) and B (3, 7) are two vertices of right triangle ABC . The hypotenuse of the triangle is AB point C is on the
kenny6666 [7]
The point C must be in a line perpendicular tothe x-axis passing through the point B(3,7), then the oordinates of point C must be (3,0)

Answer: Coordinates of point C are (3,0)
6 0
3 years ago
Andrew is 61 years. Erica is 31 years old. how many years ago was Andrew’s age 4 times Erica’s age
kozerog [31]

Answer:

21 Years Ago

Step-by-step explanation:

61 - 21 = 40

31 - 21 = 10

40/10 = 4

4 0
3 years ago
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