The frequency of the second class is 6.
Since the class width is 6 and the lower limit of the first class is 50, this means the first class goes from 50-55. This would put the second class at 56-61. There are 6 data points in this set that would go in the second class.
The lifeguard of the beach resort is on his post which is 4 m high. A boy in the pool is 9 meters away from him. Find the angle of depression from the lifeguard to the boy.
Therefore the angle of depression from the lifeguard to the boy is 24°.
Answer:
$110,212
Step-by-step explanation:
$1,137*12=13,644. Multiply by 12 for 12 months in a year
13,644*8=109,152. Rent for 8 years excluding deposit.
109,152+1060=110,212. Total Cost for 8 Years
Answer:
Kindly check explanation
Step-by-step explanation:
Length of parking lot = 20 feets
Speed of tortoise which starts at the edge = 6 feets per minute
Speed of tortoise which starts 4 feets from the edge = 2 feets per minute
Equation to represent when they will be in the same spot.
Distance = speed * time
Distance of Tortoise at edge = 6ft/min * t = 6t - - (1)
Distance of the other tortoise = (4 + 2t) - - - (2)
Equating both (1) and (2)
6t = 4 + 2t
6t - 2t = 4
4t = 4
t = 4/4
t = 1
Hence, they'll be at the same spot after 1 minute.
x=3, you can find this by using finding common bases for equation b because 243=3^5. Because of that you can get rid of three on both sides to get the equation 2x-1=5 and then just solve for x to get x=3. For the first equation 5^3=625 so that also proves x=3.
Sorry if my explanation is a little disorganized if you need more help feel free to ask
