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Lesechka [4]
3 years ago
14

Hugo works in a shop.

Mathematics
2 answers:
slava [35]3 years ago
6 0

Answer:

£111

Step-by-step explanation:

Money earned on saturday: 9*7=63

Money earned on sunday:4*9*1\frac{1}{3}=48

48+63=111

plz mark branliest

Sphinxa [80]3 years ago
6 0

Answer: he earned the sum of £132.00 that weekend.

Step-by-step explanation:Hugo is being paid 1(1/3) of his normal pay for over time in weekend . But his normal is £9.00 per hour.

On Saturday he worked 7 hrs , so his pay = 1(1/3) * £9.00 * 7 hrs

= £84.00

On Sunday he worked four(4) hours.

His pay = 1(1/3) * £9.00 * 4 hrs

= £48.00

Hostel earning for the weekend is ,

= £48 + £84

=£132.00

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The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E
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Answer:

The projected enrollment is \lim_{t \to \infty} E(t)=10,000

Step-by-step explanation:

Consider the provided projected rate.

E'(t) = 12000(t + 9)^{\frac{-3}{2}}

Integrate the above function.

E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt

E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

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2000=-\frac{24000}{3}+c

2000=-8000+c

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Now we need to find \lim_{t \to \infty} E(t)

\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000

\lim_{t \to \infty} E(t)=10,000

Hence, the projected enrollment is \lim_{t \to \infty} E(t)=10,000

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