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alexira [117]
3 years ago
7

What is the area of this figure?​

Mathematics
1 answer:
vovangra [49]3 years ago
7 0
Witch one are u takin about bc if it's the square the answer is 16 if ur taking about the rain gel the answer is 24
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Write the quadratic function in vertex form. Then identify the vertex.
ddd [48]

Answer:

Step-by-step explanation:

To put the equation into vertex form, we need to complete the square

g(x) = (x^2 - 4x + ...) - 1\\g(x) = (x^2-4x+(\frac{4}{2})^2 ) - 1 - (\frac{4}{2})^2 \\g(x) = (x-2)^2 - 5\\

This is in the form

y = a(x-h)^2 + k\\(h, k)

So, the vertex is (2, -5)

and g(x) = (x-2)^2-5

7 0
2 years ago
Why are bars of the histogram all the same width?
Aleksandr-060686 [28]
The widths of the bars are equal to ensure that numbers aren't represented improperly. If a bar was wider than another that was the same height, it could be misinterpreted as being larger. 
3 0
3 years ago
6 pounds of apples and 3 pounds of oranges cost 24 dollars.5 pounds of apples and 4 pounds of oranges cost 23 dollars. Set up a
vitfil [10]

Answer:cost of each pound of apple= $3

And cost of each pound of orange =$2

Step-by-step explanation:

Step 1

Let cost of apples = x

And cost of Oranges =y

Let 6 pounds of apples and 3 pounds of oranges cost 24 dollars be represented as

6 x + 3y= 24----- equation 1

Also, Let 5 pounds of apples and 4 pounds of oranges cost 23 dollars be represented as

5x+ 4y= 23----- equation 2

Step 2

6 x + 3y= 24----- equation 1

5x+ 4y= 23----- equation 2

Using substitution method to solve the equation

6 x + 3y= 24

24-6x=3y

y= 24-6x/3 = 8-2x

Y= 8-2x

Substituting the value of y= 8-2x  into equation 2

5x+ 4( 8-2x)= 23

5x+ 32 -8x= 23

32-23= 8x-5x

9=3x

x=9/3

x=3

Putting the value of x= 3 in equation 1 and solving to find y

6 x + 3y= 24

6(3) +3y= 24

18+3y=24

3y= 24-18

3y=6

y=6/3= 2

Therefore the cost of each pound of apple= $3

And cost of each pound of orange =$2

8 0
3 years ago
Please help me thank you.
Alexxandr [17]

Answer:

B

Step-by-step explanation:

3      -4    |   2

0      -1     |   7

3/2    -2    |   1

R1/3 ----> R1  (divide Row 1 by 3)

1       -4/3    |  2/3

0        -1      |   7

3/2      -2     |   1

R3 - 3/2  R1 -------> R3 (multiply Row 1 by 3/2 and subtract it from Row 3)

1      -4/3    |   2/3

0       -1      |    7

0       0      |    0

R2 / -1 -------> R2 (Divide Row 2 by -1)

1      -4/3   |  2/3

0        1     |   -7

0        0    |   0

R1 + 4/3 R2 --------> R1 (Multiply Row 2 by 4/3 and add it to Row 1)

1     0     |   -26/3

0    1      |      -7

0    0     |      0

5 0
3 years ago
PLEASE HELP! I'll give 5 out of 5 stars, give thanks, and give as many points as I can.
Liula [17]

Answer:

\boxed{\boxed{x=\dfrac{\pi}{3}\ \vee\ x=\pi\ \vee\ x=\dfrac{5\pi}{3}}}

Step-by-step explanation:

\cos(3x)=-1\iff3x=\pi+2k\pi\qquad k\in\mathbb{Z}\\\\\text{divide both sides by 3}\\\\x=\dfrac{\pi}{3}+\dfrac{2k\pi}{3}\\\\x\in[0,\ 2\pi)

\text{for}\ k=0\to x=\dfrac{\pi}{3}+\dfrac{2(0)\pi}{3}=\dfrac{\pi}{3}+0=\boxed{\dfrac{\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=1\to x=\dfrac{\pi}{3}+\dfrac{2(1)\pi}{3}=\dfrac{\pi}{3}+\dfrac{2\pi}{3}=\dfrac{3\pi}{3}=\boxed{\pi}\in[0,\ 2\pi)\\\\\text{for}\ k=2\to x=\dfrac{\pi}{3}+\dfrac{2(2)\pi}{3}=\dfrac{\pi}{3}+\dfrac{4\pi}{3}=\boxed{\dfrac{5\pi}{3}}\in[0,\ 2\pi)\\\\\text{for}\ k=3\to x=\dfrac{\pi}{3}+\dfrac{2(3)\pi}{3}=\dfrac{\pi}{3}+\dfrac{6\pi}{3}=\dfrac{7\pi}{3}\notin[0,\ 2\po)

7 0
3 years ago
Read 2 more answers
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