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olasank [31]
3 years ago
15

2 matchsticks have the same length as 3 bottles tops.

Mathematics
1 answer:
Phantasy [73]3 years ago
7 0
Multiply the ratio by 25 and then you will get 50 matchsticks, and 75 bottle tops :)
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Does anyone know this? I’m really stuck
S_A_V [24]

<em>p = 21</em>

Step-by-step explanation:

When you have a midsegment, the base is going to be two times as large as the midsegment. You can find the midsegment if you multiply it by two and set it equal to the base. I have attached a photo below that may help you.

This is the equation we will be using.

2(p-13)=p-5

Now let's solve! Let's start by distributing the 2 by what's in the parentheses.

2p-26=p-5

Subtract p from both sides.

p-26=-5

Add 26 to both sides.

<u>p = 21</u>

7 0
3 years ago
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A movie theature offers two containers. One container is a traiangular prism with a base area of 12cm and 19 cm of height, for $
KATRIN_1 [288]

Answer:

rectangular container

Step-by-step explanation:

Triangular prism area: A = 1/3 * base area * height

                                        = 1/3 * 12 * 19

                                        = 76 cm²

Rectangular prism: A = base area * height

                                   = 8 * 15

                                   = 120 cm²

The rectangular container has a better value because it has a bigger area and is cheaper.

Hope this helps!

3 0
3 years ago
2 2/5 x 4 = {Khan Academy}
Sophie [7]

Answer:

9.6 or 9 and 3/5

Step-by-step explanation:

turn 2 and 2 fifths into an improper fraction and multiply by four

7 0
3 years ago
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WILL MARK BRAINLIEST
s2008m [1.1K]

Answer: D

Step-by-step explanation:

3 0
3 years ago
Expand log_1/2(3x^2/2) using the properties and rules for logarithms.<br><br><br> Please help.
Naily [24]

Answer:

\frac{0.1761+2\log(x)}{-0.3010}

Step-by-step explanation:

Data provided:

\log_{1/2}(\frac{3x^2}{2})

now,

we know the properties of log functions as:

1) log(AB) = log(A) + log(B)

2) \log(\frac{A}{B}) = log(A) - log(B)

3) log(xⁿ) = n × log(x)

thus,

\log_{1/2}(\frac{3x^2}{2}) = \log_{1/2}(3x^2) - \log_{1/2}(2)

or

\log_{1/2}(\frac{3x^2}{2}) = \log_{1/2}(3)+\log_{\frac{1}{2}}(x^2) - \log_{1/2}(2)

or

using property 3

\log_{1/2}(\frac{3x^2}{2}) = \log_{1/2}(3)+2\log_{\frac{1}{2}}(x) - \log_{1/2}(2)

also,

\log_a(x)=\frac{\log(x)}{\log(a)}

thus,

\log_{1/2}(\frac{3x^2}{2}) = \frac{\log(3)}{\log(\frac{1}{2})}+2\times[\frac{\log(x)}{\log(\frac{1}{2}}]-\frac{\log(2)}{\log(\frac{1}{2})}

or

\log_{1/2}(\frac{3x^2}{2}) = \frac{\log(3)+2\log(x)-\log(2)}{\log(\frac{1}{2})}

or

\log_{1/2}(\frac{3x^2}{2}) = \frac{\log(3)+2\log(x)-\log(2)}{\log(1)-log(2)}

now,

log(1) = 0

log(2) = 0.3010

log(3) = 0.4771

thus,

\log_{1/2}(\frac{3x^2}{2}) = \frac{0.4771+2\log(x)-0.3010}{0-0.3010}

or

\log_{1/2}(\frac{3x^2}{2}) = \frac{0.1761+2\log(x)}{-0.3010}

6 0
4 years ago
Read 2 more answers
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