(5x-7)2 + 140x
= 25x2 - 70x + 14 + 140x
= 25x2 + 70x + 14
= (5x+7)2
I think it is .8 i could be wrong i’m not sure
38F Is the correct answer
It would matter, by what measurements you would go by..
You can make your own scale to go by..
That should go
Hope that this helps you..
We apply the mid point formula
That is for two points ![(x_{1} ,y_{1}) and (x_{2},y_{2})](https://tex.z-dn.net/?f=%20%28x_%7B1%7D%20%2Cy_%7B1%7D%29%20and%20%28x_%7B2%7D%2Cy_%7B2%7D%29%20%20%20)
The mid point is given by
![(\frac{(x_{1} + x_{2})}{2} , \frac{(y_{1} + y_{2})}{2} )](https://tex.z-dn.net/?f=%20%28%5Cfrac%7B%28x_%7B1%7D%20%2B%20x_%7B2%7D%29%7D%7B2%7D%20%2C%20%5Cfrac%7B%28y_%7B1%7D%20%2B%20y_%7B2%7D%29%7D%7B2%7D%20%29%20%20%20%20)
So we plug the values
![(\frac{(2m + 2p)}{2} , \frac{(2n+2r)}{2} )](https://tex.z-dn.net/?f=%20%20%28%5Cfrac%7B%282m%20%2B%202p%29%7D%7B2%7D%20%2C%20%5Cfrac%7B%282n%2B2r%29%7D%7B2%7D%20%29%20)
So we can simplify it now factor 2 on both
We get
![(\frac{(2(m+p))}{2} , \frac{(2(n+r))}{2} )](https://tex.z-dn.net/?f=%20%20%28%5Cfrac%7B%282%28m%2Bp%29%29%7D%7B2%7D%20%2C%20%5Cfrac%7B%282%28n%2Br%29%29%7D%7B2%7D%20%29%20)
we can cancel out the 2 in numerator and denominator
So
![(m+p) , (n+r)](https://tex.z-dn.net/?f=%20%28m%2Bp%29%20%2C%20%28n%2Br%29%20)
Final answer is Option D
(m+p),(n+r)