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2 years ago

A circle has a diameter with endpoints A (-4,4) and B (2,-3) . Which coordinates represent the center of the circle?

Mathematics

1 answer:

Sergio [31]2 years ago

6 0

Answer:

The coordinates of the center of the circle is (-1,-0.5)

Step-by-step explanation:

The coordinates of the center are only the midpoint coordinates of the endpoint

Mathematically, that will be;

(x,y) = (x1 + x2)/2, (y1 + y2)/2

= (-4+2)/2, (4-3)/2

= (-2/2),(-1/2)

= (-1, -0.5)

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Is 4.95 a terminating decimal

Snowcat [4.5K]

Answer:

Definitely

since the definition of a terminating decimal is one that has an ending, and a Repeating decimal is one that never ends.

Step-by-step explanation:

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2 years ago

Is 51x51 is even or odd

AURORKA [14]

You can predict that it's odd because the end of the 2 numbers is 1 and 1 x 1 is 1 and one is an odd number. (answer is odd)

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2 years ago

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the height h(t) of a trianle is increasing at 2.5 cm/min, while it's area A(t) is also increasing at 4.7 cm2/min. at what rate i

nekit [7.7K]

Answer:

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

Step-by-step explanation:

From Geometry we understand that area of triangle is determined by the following expression:

$A = \frac{1}{2}\cdot b\cdot h$ (Eq. 1)

Where:

$A$ - Area of the triangle, measured in square centimeters.

$b$ - Base of the triangle, measured in centimeters.

$h$ - Height of the triangle, measured in centimeters.

By Differential Calculus we deduce an expression for the rate of change of the area in time:

$\frac{dA}{dt} = \frac{1}{2}\cdot \frac{db}{dt}\cdot h + \frac{1}{2}\cdot b \cdot \frac{dh}{dt}$ (Eq. 2)

Where:

$\frac{dA}{dt}$ - Rate of change of area in time, measured in square centimeters per minute.

$\frac{db}{dt}$ - Rate of change of base in time, measured in centimeters per minute.

$\frac{dh}{dt}$ - Rate of change of height in time, measured in centimeters per minute.

Now we clear the rate of change of base in time within (Eq, 2):

$\frac{1}{2}\cdot\frac{db}{dt}\cdot h = \frac{dA}{dt}-\frac{1}{2}\cdot b\cdot \frac{dh}{dt}$

$\frac{db}{dt} = \frac{2}{h}\cdot \frac{dA}{dt} -\frac{b}{h}\cdot \frac{dh}{dt}$ (Eq. 3)

The base of the triangle can be found clearing respective variable within (Eq. 1):

$b = \frac{2\cdot A}{h}$

If we know that $A = 130\,cm^{2}$ , $h = 15\,cm$ , $\frac{dh}{dt} = 2.5\,\frac{cm}{min}$ and $\frac{dA}{dt} = 4.7\,\frac{cm^{2}}{min}$ , the rate of change of the base of the triangle in time is:

$b = \frac{2\cdot (130\,cm^{2})}{15\,cm}$

$b = 17.333\,cm$

$\frac{db}{dt} = \left(\frac{2}{15\,cm}\right)\cdot \left(4.7\,\frac{cm^{2}}{min} \right) -\left(\frac{17.333\,cm}{15\,cm} \right)\cdot \left(2.5\,\frac{cm}{min} \right)$

$\frac{db}{dt} = -2.262\,\frac{cm}{min}$

The base of the triangle decreases at a rate of 2.262 centimeters per minute.

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2 years ago

The measures of the angles of a triangle are in a ratio of 7:9:10. Find the measures of the angles of the triangle

Brut [27]

So all the angles in total are going to be 180 degrees.
7+9+10 = 18 (parts at all)
180/18=10 (1 part of the ratio)
Than to find all of the angles we multiply 1 part by 7, 9 and 10 separately
10*7= 70 degrees (1st angle)
10*9=90 degrees (2nd angle)
10*10=100 degrees (3rd angle)
Answer: 70, 90, 100

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2 years ago

Help ASAP with the question.

givi [52]

The answer is 5 x 10^10

Hope this helped! :)

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