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3 years ago

B

Mathematics

1 answer:

Radda [10]3 years ago

5 0

Answer:

ΔCFE is a right triangle

ΔBEC is an acute triangle

ΔBFG is an equilateral triangle

ΔGAF is an obtuse isosceles triangle

You might be interested in

Prove that 3:8 is equivalent to 12:32 use diagrams to support your answer. Use the description of equivalent ratios to support y

baherus [9]

12 divided by 3 = 4

therefore both sides must be multiplied by 4

3*4 = 12
8*4 = 32

(brainliest would be appreciated)

5 0

4 years ago

You have two coins that add up to 30 cents, and one of them is not a quarter. Which two coins are they

ruslelena [56]

Answer:

Quarter and a Nickel

Step-by-step explanation:

Sepecifically said ONE of them is not a quarter.

8 0

3 years ago

Use the Distance Formula and the Pythagorean Theorem to find the distance between each pair of points. M (10, −4) and N (2, −7)

xenn [34]

Answer:

$d=\sqrt{73}\approx8.54$

Step-by-step explanation:

So we have the two points (10,-4) and (2,-7).

And we want to find the distance between them using the Distance Formula and the Pythagorean Theorem. Let's do each one individually.

1) Distance Formula.

The distance formula is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Let's let (10,-4) be (x₁, y₁) and let's let (2,-7) be (x₂, y₂). So:

$d=\sqrt{((2)-(10))+((-7)-(-4))^2$

Simplify:

$d=\sqrt{(2-10)^2+(-7+4)^2$

Subtract:

$d=\sqrt{(-8)^2+(-3)^2$

Square:

$d=\sqrt{64+9}$

Add:

$d=\sqrt{73}$

Approximate:

$d\approx8.54$

So, the distance between (10,-4) and (2,-7) is approximately 8.54 units.

2) Pythagorean Theorem

Please refer to the graph.

So, we want to find the distance. This will be the length of the red line, or the hypotenuse.

First, let's find the length of the two legs.

The longer leg will be the difference between the two x-coordinates. So, the length of the longer leg is:

$(10-2)=8$

Note: It doesn't matter if we do 2-10, which gives -8, since we are going to square anyways. Also, distance is always positive, so 8 would be our answer.

And the shorter leg is the difference between the two y-coordinates. Namely:

$(-7-(-4))=-3=3$

So, the shorter leg is 3 units.

So now, we can use the Pythagorean Theorem, which is:

$a^2+b^2=c^2$

Substitute 8 for a and 3 for b. So:

$(8)^2+(3)^2=c^2$

Square:

$64+9=c^2$

Add:

$c^2=73$

Take the square root:

$c=\sqrt{73}\approx8.54$

This is the same as our previous answer, so we can confirm that it's correct.

So, using both the distance formula and the Pythagorean Theorem, the distance between the two points is approximately 8.54.

And we're done!

5 0

3 years ago

Read 2 more answers

Find the width of the rectangular prism when the surface area is 208 square centimeters.

ozzi

SA=2(lw+wh+lh) This is the formula for finding the surface area of a rectangular prism, where SA is surface area, l is length, w is width, and h is height.

208=2(lw+wh+lh)
104=lw+wh+lh Here, I divided both sides by 2 to get ride of the 2.

Now, I used prime factorization to find out all the prime factors of 104, which are 2, 2, 2, and 13. Since rectangular prisms only have 3 dimensions, I needed to combine two of the prime factors. In this case, I can either combine 2 of the 2s to get 2, 4, and 13 or I can combine 13 with one of the 2s to get 26, 2, and 2.

If my dimensions were 2, 4, and 13...
my surface area would be 172 sq cm.

If my dimensions were 2, 2, and 26...
my surface area would be 208 sq cm.

Hence, the width of the rectangular prism when the surface area is 208 square centimeters can be either 2 or 26.

7 0

4 years ago

Where do the lines y = 3x + 5 and y = -2x + 10 intersect?

Anna71 [15]

9514 1404 393

Answer:

(x, y) = (1, 8)

Step-by-step explanation:

A graphing calculator quickly tells you the point of intersection.

You can equate the y-values and solve for x.

3x +5 = -2x +10

5x = 5 . . . . . . . . . add 2x-5

x = 1 . . . . . . . divide by 5

3·1 +5 = y = 8 . . . . substitute for x in the first equation

The point of intersection is (x, y) = (1, 8).

6 0

3 years ago