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3 years ago

What is six less than three raised to the third power?

Mathematics

1 answer:

Nataliya [291]3 years ago

4 0

Answer:

Step-by-step explanation:

Three raise to third power can be written as $3^3$ . In this three is the base which is raised to third power.

$3^3 = 3*3*3 = 27$

Next we need to subtract 6 from Three raise to third power(i.e from 27)

which can be written mathematically as

$3^3 - 6 = 3*3*3 - 6 \\=> 27 - 6 = 21$

Hence 6 less than three raised to the third power is 21 as explained above.

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3 years ago

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3 years ago

What are m∠1 and m∠2?

zaharov [31]

Answer:

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Step-by-step explanation:

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2 years ago

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3 years ago

Read 2 more answers

Please help!! What Find the Error and explain why it is wrong!

Nata [24]

Answer:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

Step-by-step explanation:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. The real numerator in Step E should be:

$3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x$

Hence, Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

And further steps are described below:

Step D

$x^{2}-x+4 = 0$