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Pani-rosa [81]
3 years ago
13

There are 321 crayons in a box and 204 crayons on the floor. About how many fewer than 1,000 crayons are there? Estimate. Then s

olve. The estimated number of crayons fewer than 1,000
Mathematics
1 answer:
zimovet [89]3 years ago
3 0

Answer:

1000 - 300 - 200 = 500

Step-by-step explanation:

estimation

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Yaro buys a baseball cap for $9.50. He also buys a new baseball. Yaro speads $13.50 altogether.
VMariaS [17]

Answer:

13.5 = 9.5 + x

x=4

Step-by-step explanation:

In this problem, the price of the baseball cap, which is $9.50, and a baseball, whose price is unknown (and therefore must be the variable), total $13.50. So, to set up the equation add the two prices and set them equal to the total, 9.5+x=13.5.

Then, using the subtraction property of equality subtract 9.5 from both sides. This means x=4, so the baseball cost 4 dollars.

4 0
2 years ago
Joe has fraction 5 over 6 pound of bird seed. He needs Fraction 1 over 3. pound to feed the birds daily. Which of the rectangle
Studentka2010 [4]
I divided the two fractions & drew a model.

\frac{5}{6}/ \frac{1}{3} = 2.5

So we know that the bird seed will last 2.5 days.

Knowing this, we can go with:

B. Rectangle model divided into six equal sections, five sections are labeled five-sixths and two sections are labeled one-third, equaling two and one-half days.

Let me know if you find any problems with my answer.


9 0
2 years ago
What is the general equation of a cosine function with an amplitude of 3, a period of 4 pi, and a horizontal shift of negative p
liberstina [14]

The cosine function with the given characteristics is:

f(x) = 3*cos(x/2 - pi).

<h3>How to get the cosine function?</h3>

The general cosine function is:

f(x) = A*cos(kx + p)

Where A is the amplitude and p is the phase, then we know that:

A = 3

p = -pi

Then we have:

f(x) = 3*cos(kx - pi)

And the period is equal to 4pi, then we must have that:

k*(x + 4pi) - pi = k*x - pi + 2pi

k = 1/2

Then the function is:

f(x) = 3*cos(x/2 - pi).

If you want to learn more about cosine functions:

brainly.com/question/4372174

#SPJ4

3 0
2 years ago
Hi. Please I need help with these questions.
ElenaW [278]

Answer:

Q 12 roots of the equation

2x^{2} -6+1=0 \\= (x-\frac{\sqrt{10} }{2})(x+\frac{\sqrt{10} }{2})\\

∝ = \frac{\sqrt{10} }{2}

β = -\frac{\sqrt{10} }{2}

no matter if u oppose the root

(i) 2(\frac{\sqrt{10} }{2})(-\frac{\sqrt{10} }{2} )^{2}+2(\frac{\sqrt{10} }{2} )^{2}(-\frac{\sqrt{10} }{2})+2(

(ii)((\frac{\sqrt{10} }{2})^{2} - 3 (\frac{\sqrt{10} }{2})(-\frac{\sqrt{10} }{2}) + ((-\frac{\sqrt{10} }{2})^{2}) = \frac{25}{2}

Q 13  roots of equation

4x^{2} -3x-4=0\\\alpha = -0.693\\\beta = 1.443

the roots of the second equation are

x1 = 1/3(-0.693) = -0.231

x2 = 1/3(1.443) = 0.481

the equation is

(x+0.231)(x-0.481)=0

x^{2}-\frac{1}{4} x-\frac{1}{9}

4 0
3 years ago
Help please! 15 points!
Phantasy [73]
♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️
y=(1/5)x+12/5
♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️
8 0
3 years ago
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