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For large sample confidence intervals about the mean you have:
xBar ± z * sx / sqrt(n)
where xBar is the sample mean z is the zscore for having α% of the data in the tails, i.e., P( |Z| > z) = α sx is the sample standard deviation n is the sample size
We need only to concern ourselves with the error term of the CI, In order to find the sample size needed for a confidence interval of a given size.
z * sx / sqrt(n) = width.
so the z-score for the confidence interval of .98 is the value of z such that 0.01 is in each tail of the distribution. z = 2.326348
The equation we need to solve is:
z * sx / sqrt(n) = width
n = (z * sx / width) ^ 2.
n = ( 2.326348 * 6 / 3 ) ^ 2
n = 21.64758
Since n must be integer valued we need to take the ceiling of this solution.
n = 22
Answer:
Given the expression: 
Let the value of the given expression in radians be 
then;
......[1]
We know the value of 
Substitute the given value in [1] we have;
Since, the value of 
is 0, therefore, the value of is in the form of:
; where n is the integer.
At n =0, 1 and 2, {Since, n is the integer}
Value of 
and 
therefore, the answer in radians either 
or
Answer
Step-by-step explanation:
One solution :
x = -1/3 = -0.333
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
-5*(3*x+1)+4*x-(10*x+2)=0
Step by step solution :
Step 1 :
Equation at the end of step 1 :
((0 - 5 • (3x + 1)) + 4x) - (10x + 2) = 0
Step 2 :
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
-21x - 7 = -7 • (3x + 1)
Equation at the end of step 3 :
-7 • (3x + 1) = 0
Step 4 :
Equations which are never true :
4.1 Solve : -7 = 0
Answer:
The answer is C, 220 units.
