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Ahat [919]
3 years ago
5

15:3 in simplest form

Mathematics
1 answer:
sesenic [268]3 years ago
7 0

Answer:5:1

Step-by-step explanation: Divide 15:3 by common factors to get 5:1

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Rhombus ABCD has a diagonal BD¯¯¯¯¯.
ELEN [110]

Answer:

Solution given:

m∠ADB=(4x−12)°

m∠CDB=(3x+6)°

m∠ADC =?

Since diagonal BD bisect the angle <ADC

so

m∠ADB= m∠ADC

(4x-12)°=(3x+6)°

4x-3x=6-12

x=12+6

x=18°

again.

<ADB=m∠ADB+ m∠ADC=4×18-12+3×18+6=120°

So

<u>the m∠</u><u>ADC</u><u> </u><u>=</u><u>1</u><u>2</u><u>0</u><u>°</u>

5 0
3 years ago
Answer This Please With explanation If You do I Will Mark Brainliest
4vir4ik [10]

Answer:

8)61.5 9)42.1

Step-by-step explanation:

8)61.5

area of square 10×10=100

circle=pie r^2

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100-38.5=61.5

9)14×14=196

14/2=7

7=radius

pie×7^2

=153.9/2(because circle is half)

=76.95

76.95×2

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42.1

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6 0
2 years ago
Which is the graph of r = 6 cos?
Alex777 [14]

Answer:

Using the formula

r

=a

cos

(

θ

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or

r

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a

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θ

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r

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cos

(

θ

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Step-by-step explanation:

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