Answer:
Solution given:
m∠ADB=(4x−12)°
m∠CDB=(3x+6)°
m∠ADC =?
Since diagonal BD bisect the angle <ADC
so
m∠ADB= m∠ADC
(4x-12)°=(3x+6)°
4x-3x=6-12
x=12+6
x=18°
again.
<ADB=m∠ADB+ m∠ADC=4×18-12+3×18+6=120°
So
<u>the m∠</u><u>ADC</u><u> </u><u>=</u><u>1</u><u>2</u><u>0</u><u>°</u>
Answer:
8)61.5 9)42.1
Step-by-step explanation:
8)61.5
area of square 10×10=100
circle=pie r^2
3.5^2×pie
=38.5
100-38.5=61.5
9)14×14=196
14/2=7
7=radius
pie×7^2
=153.9/2(because circle is half)
=76.95
76.95×2
=153.9
=196-153.9
42.1
MARK IT BRAINLIEST
Answer:
Using the formula
r
=a
cos
(
θ
)
or
r
=
a
sin
(
θ
), graph the circle.
r
=
6
cos
(
θ
)
Step-by-step explanation:
Ooooppppppp— homie not gettin nun at home I see
I believe the answer is x=24
