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Verdich [7]
3 years ago
5

Consider a binomial distribution of 200 trials with expected value 80 and standard deviation of about 6.9. Use the criterion tha

t it is unusual to have data values more than 2.5 standard deviations above the mean or 2.5 standard deviations below the mean to answer the following questions.
(a) Would it be unusual to have more than 120 successes out of 200 trials? Explain.

(A) Yes. 120 is more than 2.5 standard deviations above the expected value.
(B) Yes. 120 is more than 2.5 standard deviations below the expected value.
(C) No. 120 is less than 2.5 standard deviations above the expected value.
(D) No. 120 is less than 2.5 standard deviations below the expected value.
Mathematics
1 answer:
mote1985 [20]3 years ago
5 0

Answer:

The correct answer is option 'a' : 120 is more than 2.5 standard deviations above the expected value.

Step-by-step explanation:

For an exponential distribution we have

The expected value μ = 80

No of trails n = 200

Thus we have

p=\frac{80}{200}=0.4

The deviation is related to expected value and probability as

\sigma =\sqrt{np(1-p)}\\\\\therefore \sigma =\sqrt{200\cdot 0.4\cdot (1-0.4)}=6.9

Thus the values between the given deviation is

x_{1}=80-2.5\times 6.9=62.75\\\\x_{2}=80+6.9\times 2.5=97.25

Now since 120 successes are out of the range of [62.75,97.25] thus 120 is more than the expected value.

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9 . a/9=9(-4)
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a=9 . -4
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6 0
3 years ago
URGENT! PLEASE HELP.
Harrizon [31]

The distance BC from Tower 2 to the plane will be 14,065.5 ft and the height of the plane from the ground will be 5,720.9 ft.

<h3>What is a right-angle triangle?</h3>

It is a type of triangle in which one angle is 90 degrees and it follows the Pythagoras theorem and we can use the trigonometry function.

A plane is located at C on the diagram.

There are two towers located at A and B.

The distance between the towers is 7600 feet and angles of elevation are given.

Then in the right-angle triangle ΔADC, we have

\rm \tan 16 = \dfrac{H}{7600 + X}\\\\\\H = 0.2867(7600 +X)\\\\\\H = 0.2756\ X + 2179.2649 ...1

Then in the right-angle triangle ΔBDC, we have

\rm \tan24 = \dfrac{H}{ X}\\\\\\H = 0.4452\ X ...2

From equations 1 and 2, we have

0.4452X = 0.2756 X + 2179.2649

0.1696X = 2179.2649

            X = 12849.439 ≅ 12,849.4 ft

Then the distance BC from Tower 2 to the plane will be

\rm BC = \dfrac{12849.4}{\cos 24}\\\\\\BC = 14065.5 \ ft

Then the height of the plane from the ground will be

\rm H = 12849.4 \times  \tan 24 \\\\\\H = 5720.9 \ ft

The figure is shown below.

More about the right-angle triangle link is given below.

brainly.com/question/3770177

#SPJ1

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2 years ago
Perform the indicated operation <br> 5(3x^3)^3-2(3x^3)
Pie
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= 135x^9 - 6x^3
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3 years ago
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11111nata11111 [884]

Remark

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Givens

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Formula

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3 years ago
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iogann1982 [59]
Yeah that is correct. 3/4 is equal to .75
7 0
3 years ago
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