Answer: option D is the answer
Step-by-step explanation:
Answer:
A minimum of 10 dimes and 11 quarters is what Alexandra will have
Step-by-step explanation:
Let
d = number of dimes
q = number of quarters
Since she has 21 coins altogether,
d + q = 21------------------------equation 1
- If these coins are worth $3.75 then
0.10 x d + 0.25 x q = 3.75
- which is 0.10d +.25q =3.75
--------------------------equation 2
where $.10 is the value of one dime and $.25 is the value of one quarter
make d the subject of formula from equation 1 d = 21 -q----------equation 3
insert it in equation 2
0.10d +0.25q =3.75
0.10(21-q) + 0.25q = 3.75
0.1(21)-0.1q+0.25q=3.75
2.1 +0.15q = 3.75
0.15q = 3.75-2.1 = 1.65
q = 1.65/0.15 =165/15 =11
- since we have the value of q insert in equation 3
d = 21 - q
d = 21-11
d = 10
Alexandra has 10 dimes and 11 quarters.
from my calculation i can see that the a minimum of 10 dimes and 11 quarters is what Alexandra will have
Note that 1lb=16oz and set up multiplication/division to cancel out units that you do not need for the final answer. (Units cancel just like numbers, this is fundamental to dimensional analysis)
64oz($1.50/16oz)=$6.00
Answer:
$625
Step-by-step explanation:
If Todd has to pay $14,000 in tuition for his school each year and uses $6,500 in financial aid each year all for 2 years, the money he needs to save can be modeled by:
2(-$14000 + $6500) + 2(12x) = 0.
x is the minimum amount of money he needs to save in order to cover this expense without debt.
Thus 2(-$14000 + $6500) + 2(12x) = 0 →
2(-$7500) + 24x = 0 → -$15000 + 24x = 0 →
24x = $15000 → x = $625
