For this case we have that the generic equation of the line is given by:

Where,
m: slope of the line
b: intersection with the y axis.
Since the line is parallel to PQ, then the slopes are equal.
We have then:

On the other hand we have:

Substituting values we have:
Answer:
The equation of the line that is parallel to line PQ and that has the and intercept b = -3 is:
Add 7 to both sides
3x + 12 = 7x
Subtract 3x
12 = 4x
Divide by 4
x = 3
Answer: D, or 1+cotangent squared theta= cosecant squared theta
Step-by-step explanation: Took the test it is right
Answer:look below
Step-by-step explanation:
To graph y= 4x +2 plot the point (0,2) on the graph because the y-intercept is 2 then use the slope: 4 to find another point. Another point would be (1,6).