For the first line we have a slope of (y2-y1)/(x2-x1)
(2--2)/(1--1)=4/2=2 so we have:
y=2x+b, now solve for b with either of the points, I'll use: (1,2)
2=2(1)+b
b=0 so the first line is:
y=2x
Now the second line:
(1-10)/(4--2)=-9/6=-3/2 so far then we have:
y=-3x/2+b, using point (4,1) we solve for b...
1=-3(4)/2+b
1=-6+b
b=7 so
y=-3x/2+7 or more neatly...
y=(-3x+14)/2
...
The solution occurs when both the x and y coordinates for each are equal, so we can say y=y, and use our two line equations...
2x=(-3x+14)/2
4x=-3x+14
7x=14
x=2, and using y=2x we see that:
y=2(2)=4, so the solution occurs at the point:
(2,4)
Answer:
On the right is a circle with centre (0, 0), radius r and (x, y) any point on the circle. Distance between (0,0) and (x, y) equals the radius, r. If the centre is (0, 0), the equation of the circle will be of the form x2 + y2 = r2.
Yes they are equal. 45 is a multiple of 15. 45/15=3, 7*3=21. so 21/45 is equal to 7/15.
Answer:
m(C)<m(B)<m(A).
Step-by-step explanation:
1) according to the condition the shortest side is AB, the longest side is BC, the middle is AC. Then
2) the smallest angle is BCA (or C), the middle angle is ABC (or B), the largest angle is BAC (or A).
