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Assoli18 [71]
3 years ago
13

Cube root of - 1000p^12q^3

Mathematics
1 answer:
aleksley [76]3 years ago
7 0
\bf \sqrt[3]{-1000p^{12}q^3}~~
\begin{cases}
1000=10^3\\
(-1)^3=-1\cdot -1\cdot -1\\
\qquad -1\\
p^{12}=p^{4\cdot 3}\\
\qquad (p^4)^3
\end{cases}\implies \sqrt[3]{(-1)^3(10)^3(p^4)^3q^3}
\\\\\\
(-1)(10)p^4q\implies -10p^4q
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