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2 years ago

Please!!!!!! Help!!!! And both are different

Mathematics

2 answers:

Shalnov [3]2 years ago

5 0

Answer:

if ur du ur us du

Step-by-step explanation:

ur ydxurxru

daser333 [38]2 years ago

4 0

840 mm2
OR 840 square millimeters
OR 840 millimeters squared

All of the units of measurement are the same. Since i dont know whats in the dropdown menu, just choose one of those answers I gave that matches with the choices on your dropdown menu

MARK ME BRAINLIEST TYSM!
Com.ment me if u have any questions

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Evaluate -4|-4|. A) 8 B) -8 C) 16 D) -16

Papessa [141]

The answer

The answer is -16

8 0

2 years ago

Read 2 more answers

What is the Gcf of 10,20,78

Ksivusya [100]

The answer to this is 2. Ten only has two factors, 5 and 2, and 2 can be decided evenly amongst them all.

7 0

3 years ago

Please help I will give brainliest to whoever answers this question

pantera1 [17]

Hi!

To solve this, we must make an equation in y = mx + b form, where m is the slope and b is the y-intercept.

Since we are looking at a graph with points, it saves us a TON of work, and all we have to do is simply look at the graph. We only need to find m and b, that's it!

M is the slope, and the slope can be represented by the change between points on a line, also known as rise/run.

If we start at point (-4, -1), and go to point (-2, 0), we can see that it goes up 1 and right 2, which would be represented as 1/2.

B is the y-intercept, and that is simply the point that is on the y-axis, which is the point (0, 1), so our number would be 1.

Therefore, plugging these numbers into the equation, our equation is y = 1/2x + 1

Hope this helps! :D

6 0

2 years ago

Hem dibuixat tres rectangles. En el primer, la llargada mesura 3 cm més que l'amplada. El segon i tercer rectangle tenen unes di

quester [9]

Resposta:

Primer rectangle:

Amplada = 11

Longitud = 14

Segon rectangle:

Amplada = 12

Longitud = 15

Tercer rectangle:

Amplada = 13

Longitud = 16

Explicació pas a pas:

Donat que:

Primer rectangle:

Amplada = x

Longitud = x + 3

2n rectangle:

Augment de la dimensió d'1 cm respecte al primer rectangle;

Amplada = x + 1

Longitud = x + 4

3r rectangle:

Augment de la dimensió de 2 cm respecte al primer rectangle;

Amplada = x + 2

Longitud = x + 5

Suma dels tres perímetres del rectangle:

Perímetre d'un rectangle: 2 (l + O)

Primer rectangle:

2 (x + x + 3) = 2 (2x + 3) = 4x + 6

2n:

2 (x + 1 + x + 4) = 2 (2x + 5) = 4x + 10

3r:

2 (x + 2 + x + 5) = 2 (2x + 7) = 4x + 14

Suma de perímetres = 162

(4x + 6 + 4x + 10 + 4x + 14) = 162

12x + 30 = 162

12x = 162 - 30

12x = 130

x = 11

Per tant,

Primer rectangle:

Amplada = 11

Longitud = 11 + 3 = 14

2n rectangle:

Amplada = 11 + 1 = 12

Longitud = 11 + 4 = 15

3r rectangle:

Amplada = 11 + 2 = 13

Longitud = 11 + 5 = 16

8 0

3 years ago

A average amount of money on deposit in a savings account is $7500. Suppose a random sample of 49 accounts shows the average in

Valentin [98]

Answer:

z=-3.79

$p_v =2*P(z$

Step-by-step explanation:

1) Data given and notation

$\bar X=6850$ represent the mean average amount of money on deposit in savings account for the sample

$\sigma=1200$ represent the population standard deviation for the sample

$n=49$ sample size

$\mu_o =7500$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean for the amount of money on deposit in savings account differs from 7500, the system of hypothesis would be:

Null hypothesis: $\mu =7500$

Alternative hypothesis: $\mu \neq 7500$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{6850-7500}{\frac{1200}{\sqrt{49}}}=-3.79$

4)P-value

Since is a two-sided test the p value would be:

$p_v =2*P(z$

5) Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the average amount of money deposit in savings account its significantly different from 7500 tons at 1% of signficance.

7 0

3 years ago