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3 years ago

What is the maximum number of relative extrema a polynomial function can have?

1 answer:

4 0

Relative extrema occur where the derivative is zero (at least for your polynomial function). So taking the derivative we get

20x3−3x2+6=0

 This is a 3rd degree equation, now if we are working with complex numbers this equation is guaranteed to have 3 solutions by the fundamental theorem of algebra. But the number of real roots are 1 which can be found out by using Descartes' rule of signs. So the maximum number of relative extrema are 1.

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What is the solution to -3/4x

zubka84 [21]

Answer:

3x/4

Step-by-step explanation:

that's what I found. It would be better if u had more details in your question.

5 0

3 years ago

Which sets of numbers are closed under subtraction?

stealth61 [152]

Integers are closed under subtraction.

3 0

3 years ago

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HELPP!! Select the correct answer. What is the value of arcsin ?

Schach [20]

For this case we have that by definition, it is called arcsine (arcsin) from a number to the angle that has that number as its sine.

We must find the $arcsin (\frac {\sqrt {2}} {2})$ . Then, we look for the angle whose sine is $\frac {\sqrt {2}} {2}$ .

We have to, by definition:

$Sin (45) = \frac {\sqrt {2}} {2}$

So, we have to:

$arcsin (\frac {\sqrt {2}} {2}) = 45$

Answer:

Option B

5 0

4 years ago

Read 2 more answers

5a – 10b = 45, when b = 3

balandron [24]

Well, since you have the value of b, the first thing you want to do is substitute that value in for b.

5a - 10(3) = 45

10*3 = 30

5a - 30 = 45

Now, to get the variable by itself (a) you have to + 30 because you have to reverse the subtraction.

5a = 75

Now, you divide by 5 to finish getting a by itself.

a = 15

Hope this helps!

6 0

3 years ago

Read 2 more answers

My friend sets out walking at a speed of $3$ miles per hour. I set out behind her $5$ minutes later at $4$ miles per hour. When

r-ruslan [8.4K]

Answer: The answer is 0.25 miles.

Step-by-step explanation: Given that my friend started walking at a speed of 3 miles per hour and I started 5 minutes after him at a speed of 4 miles per hour. We need to find the number of miles my friend travelled when I started walking.

Since I started 5 minutes after than my friend, so we are to find the distance travelled by my friend in 5 minutes.

In 1 hour, i.e., 60 minutes, distance travelled by my friend = 3 miles.

In 1 minute, distance travelled by my friend is

$\dfrac{3}{60}=\dfrac{1}{20}~\textup{miles}.$

Therefore, distance travelled by my friend in 5 minutes will be

$\dfrac{1}{20}\times 5=\dfrac{1}{4}=0.25~\textup{miles}.$

Thus, the answer is 0.25 miles.

3 0

3 years ago

Read 2 more answers