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3 years ago

In the drawing below, PQ is parallel to ST. Triangle PQR is similar to triangle TSR.

Mathematics

2 answers:

Lerok [7]3 years ago

6 0

Answer:

PR corresponds to TR.

Step-by-step explanation:

Its the second choice:

PR corresponds to TR.

This is because they are opposite equal angles ( < Q and <S).

Reika [66]3 years ago

3 0

Answer:

PR corresponds to TR

Step-by-step explanation:

<Q and <S are pair of alternate angles [since PQ is parallel to ST]

<Q = <S [since they are alternate angles]

So, PR corresponds to TR [since they are opposite sides of alternate angles and ΔPQR is similar to ΔTSR]

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What is the area of the composite figure? (use 3.14 for pi). Explain how you arrived at your answer. Please round to the nearest

maksim [4K]

The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.

Step-by-step explanation:

The given is,

Given diagram is combination of Rectangle and Semi circle.

Step:1

Res the attachment,

Area of given diagram = Area of A + Area of B..............(1)

Step:2

For A,

The A section in the given diagram is semi circle,

Diameter of semi circle = Total distance - ( 2+3)

( ∵ 2, 3 are top distance in the given diagram)

$= 10 - 5$

Diameter, d = 5 cm

Radius, $r = \frac{d}{2}$

$r = \frac{5}{2}$

r = 2.5 cm

Area, $A_{A} = \frac {\pi r^{2} }{2}$ ........................(2)

$A_{A} = \frac {\pi (2.5)^{2} }{2}$

$= \frac {\pi ( 6.25) }{2}$

$= \frac{19.63}{2}$

$A_{A} = 9.8174 cm^{2}$

Step:3

For B,

Area of rectangle is,

$A_{B} =lb$ .....................(3)

Where, l - Length = 10 cm

b - Width = 2 cm

Equation (3) become,

$= (10)(2)$

$= 20$

Area of B, $A_{B}$ = 20 $cm^{2}$

Step:4

From the equation (1),

Area of given diagram = 20+ 9.81747

Area = 29.817 square centimeters

Result:

The area of the given diagram is 29.817 square centimeters. The given diagram is combination of rectangle and semi circle.

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Harlamova29_29 [7]

Answer:

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