Answer:
5/8 of a cup
Step-by-step explanation:
A hyperbola with a center at (0, 0) can be defined as x²/a² − y²/b² = ±1.<span>
</span>The statement "<span>The symmetry of a hyperbola with a center at (h, k) only occurs at y = k" </span>is false, because a hyperbola have many different orientations.
It doesn't have to be symmetric about the lines y = k or x = h.
128 = a + + 4(a + 10) + (a + 10)
128 = a + 4a + 40 + a + 10
128 = 6a + 50
128-50 = 6a
78 = 6a
13 = a
1st = a = 13
2nd = 4(a + 10) = 4(23) = 92
3rd = a + 10 = 23
Answer:
The numbers
such that the average value of
on the interval [0, b] is equal to 8 are
and
.
Step-by-step explanation:
The mean value of function within a given interval is given by the following integral:

If
,
,
and
, then:





The roots of this polynomial are determined by the Quadratic Formula:
and
.
The numbers
such that the average value of
on the interval [0, b] is equal to 8 are
and
.
Answer: Perimeter = 40
Area = 204
Step-by-step explanation:
Perimeter is the sum of all the sides:
11 + 12 + 17 = 40
The area of a triangle is 1/2 base x height
1/2( 17 x 24)
1/2( 408) = 204