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3 years ago

What's a unknown point thats y-coordinate is zero.

Mathematics

1 answer:

klemol [59]3 years ago

4 0

Answer:

an unknown point? like 0,7 or 0,5 or 0,1 or 0,0 or 0,anything?

Step-by-step explanation:

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If seven cats killed seven rats in 7 min, how many cats are needed to kill 200rats in 100min

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Light travels 9.45 \cdot 10^{15}9.45⋅10 15 9, point, 45, dot, 10, start superscript, 15, end superscript meters in a year. t

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We are given that the distance light travel is:

9.45 x 10^15 meters / year

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Circles are described below by the coordinates of their centers, C, and one point on their circumference, A. Determine an equati

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Using the given center and point at the circumference, the equation of the circles are:

a) $(x - 5)^2 + (y - 2)^2 = 100$

b) $(x + 2)^2 + (y + 5)^2 = 169$

c) $(x - 5)^2 + (y + 1)^2 = 65$

<h3>What is the equation of a circle?</h3>

The equation of a circle of radius r and center $(x_0,y_0)$ is given by:

$(x - x_0)^2 + (y - y_0)^2 = r^2$

Item a:

Center C(5,2), hence $x_0 = 5, y_0 = 2$ .

The point at the circumference is A(11,10), hence:

$(x - 5)^2 + (y - 2)^2 = r^2$

$(11 - 5)^2 + (10 - 2)^2 = r^2$

$r^2 = 100$

Hence:

$(x - 5)^2 + (y - 2)^2 = 100$

Item b:

Center C(-2,-5), hence $x_0 = -2, y_0 = -5$ .

The point at the circumference is A(3,-17), hence:

$(x + 2)^2 + (y + 5)^2 = r^2$

$(3 + 2)^2 + (-17 - 5)^2 = r^2$

$r^2 = 169$

Hence:

$(x + 2)^2 + (y + 5)^2 = 169$

Item c:

Center C(5,-1), hence $x_0 = 5, y_0 = -1$ .

The point at the circumference is A(-2,-5), hence:

$(x - 5)^2 + (y + 1)^2 = r^2$

$(-2 - 5)^2 + (-5 + 1)^2 = r^2$

$r^2 = 65$

Hence:

$(x - 5)^2 + (y + 1)^2 = 65$

You can learn more about equation of a circle at brainly.com/question/24307696

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