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Likurg_2 [28]
3 years ago
6

What's a unknown point thats y-coordinate is zero.

Mathematics
1 answer:
klemol [59]3 years ago
4 0

Answer:

an unknown point? like 0,7 or 0,5 or 0,1 or 0,0 or 0,anything?

Step-by-step explanation:

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Light travels 9.45 \cdot 10^{15}9.45⋅10 ​15 ​​ 9, point, 45, dot, 10, start superscript, 15, end superscript meters in a year. t
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We are given that the distance light travel is:

9.45 x 10^15 meters / year

 

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Circles are described below by the coordinates of their centers, C, and one point on their circumference, A. Determine an equati
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Using the given center and point at the circumference, the equation of the circles are:

  • a) (x - 5)^2 + (y - 2)^2 = 100
  • b) (x + 2)^2 + (y + 5)^2 = 169
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<h3>What is the equation of a circle?</h3>
  • The equation of a circle of radius r and center (x_0,y_0) is given by:

(x - x_0)^2 + (y - y_0)^2 = r^2

Item a:

  • Center C(5,2), hence x_0 = 5, y_0 = 2.

The point at the circumference is A(11,10), hence:

(x - 5)^2 + (y - 2)^2 = r^2

(11 - 5)^2 + (10 - 2)^2 = r^2

r^2 = 100

Hence:

(x - 5)^2 + (y - 2)^2 = 100

Item b:

  • Center C(-2,-5), hence x_0 = -2, y_0 = -5.

The point at the circumference is A(3,-17), hence:

(x + 2)^2 + (y + 5)^2 = r^2

(3 + 2)^2 + (-17 - 5)^2 = r^2

r^2 = 169

Hence:

(x + 2)^2 + (y + 5)^2 = 169

Item c:

  • Center C(5,-1), hence x_0 = 5, y_0 = -1.

The point at the circumference is A(-2,-5), hence:

(x - 5)^2 + (y + 1)^2 = r^2

(-2 - 5)^2 + (-5 + 1)^2 = r^2

r^2 = 65

Hence:

(x - 5)^2 + (y + 1)^2 = 65

You can learn more about equation of a circle at brainly.com/question/24307696

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