Answer: y = v₀tgθx - gx²/2v₀²cos²θ
a = v₀tgθ
b = -g/2v₀²cos²θ
Step-by-step explanation:
x = v₀ₓt
y = v₀y.t - g.t²/2
x = v₀.cosθt → t = x/v₀.cosθ
y = v₀y.t - g.t²/2
v₀y = v₀.senθ
y = v₀senθ.x/v₀cosθ - g/2.(x/v₀cosθ)²
y = v₀.tgθ.x - gx²/2v₀²cos²θ
a = v₀tgθ → constant because v₀ and θ do not change
b = - g/2v₀²cos²θ → constant because v₀, g and θ do not change
It’s a little surprising that this question didn’t come up earlier. Unfortunately, there’s no intuitive way to understand why “the energy of the rest mass of an object is equal to the rest mass times the speed of light squared” (E=MC2). A complete derivation/proof includes a fair chunk of math (in the second half of this post), a decent understanding of relativity, and (most important) experimental verification.
Answer:
6/8 y=79
my id has now been sent off
Answer:
use distributive property of the parenthesis first so
4+42-21+8 = 33
An orthocenter is the intersection of three <u>Altitudes in a triangle</u>
<u></u>
Explanation:
Cos milky said it.
