Question

In the pendulum formula , we use g = 9.8 m/s2 for the acceleration due to gravity on Earth. But what about on the Moon? If an astronaut on the surface of the moon swings a 1-meter long pendulum, and it has a period of 4.9 seconds, what is the acceleration due to gravity, g, on the moon?

Answer 1

Answer:

The acceleration due to gravity on the moon is 1.642 m/s².      

Step-by-step explanation:

Given : In the pendulum formula , we use g = 9.8 m/s2 for the acceleration due to gravity on Earth. If an astronaut on the surface of the moon swings a 1-meter long pendulum, and it has a period of 4.9 seconds.

To find : What is the acceleration due to gravity, g, on the moon?        

Solution :

The pendulum formula is $T=2\pi \sqrt{\frac{L}{g}}$

where, T is the time period,

L is the length of the pendulum,

g is the acceleration due to gravity

We have to find the value of g acceleration due to gravity on the moon.

The formula became,

$g'=(\frac{2\pi}{T})^2\times L$

Substitute T=4.9 seconds , L= 1 m

$g'=(\frac{2\times 3.14}{4.9})^2\times 1$

$g'=(\frac{6.28}{4.9})^2$

$g'=\frac{39.4384}{24.01}$

$g'=1.642$

The acceleration due to gravity on the moon is 1.642 m/s².

Answer 2

Answer for APEX
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1.6 m/s^2