Area(A)= lw
perimeter(P)= 2w+2l= 34in
length(l)= w+5
width(w)= w
1/2 P= 17= w+l
17= w+(w+5)
17= 2w+5
2w=12
w=6 in
l= w+5
l= 6+5
l=11 in
A= lw= (11)(6)= 66in²
Answer:
Area of rectangle is 66 in².
Answer:
22.5
Step-by-step explanation:
What you need to do is calculate the volume of the Box. With the box being the volume of the piramid added to the prism surrounding the box with volume 15.
If you want to calculate it yourself stop reading here, because I will work it out now.
Volume box = a*b*c
Volume prism = 15
Volume pyramid = (b * c * a)/3
The prism has the volume of the box minus the pyramid so
abc - (abc)/3 = 15
abc - (1/3)abc = 15
(2/3)abc = 15
abc = 22.5
So 22.5 is the volume of the figure
Answer: B
Step-by-step explanation:
If those are the possible answers i'm pretty sure you need to have a group of numbers you extract the mean from for example form the numbers 56, 77, 65, 87, and 99 the mean of the numbers would be 77 so once i have those we can figure it out
Greetings from Brasil...
Rewriting the problem sets
A = {-7, 4, 2, 14, 21, 34, 42}
B = {...; 2; 4; 6; 8; 10; 12; 14; 16; 18; 20; 22; 24; 26; 28; 30; 32; 34; 36; 38; 40; 42;...}
C = {...; -14; -7; 0; 7; 14; 21; 28; 35; 42; 49; 56; 63; 70; 77;...}
So, according to the statement, it is desired:
A ∩ B ∩ C - the intersection between the 3 sets, that is, which numbers are present simultaneously in the 3 sets....
Looking at the sets we conclude that
<h3>A ∩ B ∩ C = {14; 42}</h3>
