1 answer:
Answer:
x = -1, x = 1
Step-by-step explanation:
Factor the equation. (It's a difference of squares, so we know the form will be (a-b)(a+b).)
![y = x^{2} - 1\\y = (x-1)(x+1)](https://tex.z-dn.net/?f=y%20%3D%20x%5E%7B2%7D%20-%201%5C%5Cy%20%3D%20%28x-1%29%28x%2B1%29)
Test this by FOILing it out, if you're unsure. This is something it can be good to memorize!
Set it equal to 0.
![0 = (x+1)(x-1)](https://tex.z-dn.net/?f=0%20%3D%20%28x%2B1%29%28x-1%29)
Separate the two parenthetical expressions by the Zero Product Property.
![0 = x+1\\0 = x-1](https://tex.z-dn.net/?f=0%20%3D%20x%2B1%5C%5C0%20%3D%20x-1)
Solve for x!
![x=-1, x=1](https://tex.z-dn.net/?f=x%3D-1%2C%20x%3D1)
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