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galina1969 [7]
3 years ago
11

Which line segment is an altitude of ΔVWY?

Mathematics
1 answer:
Paha777 [63]3 years ago
3 0

Answer:

x

Step-by-step explanation:

just trust I know the x is the altitude

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I’d really appreciate some help :)
olga2289 [7]

Answer/Step-by-step explanation:

The corresponding side lengths of two triangles are always equal. Apply this in solving for x

4. \frac{9}{6} = \frac{x}{5}

Cross multiply

6*x = 5*9

6x = 45

divide both sides by 6

y = 7.5

5. \frac{10}{8} = \frac{x}{11}

Cross multiply

8*x = 10*11

8x = 110

divide both sides by 8

x = 13.75

6. \frac{12}{x} = \frac{7}{4}

Cross multiply

x*7 = 12*4

7x = 48

divide both sides by 7

x = 6.86 (nearest hundredth)

7 0
3 years ago
Taylor is buying a new flashlight. He can choose from red, blue, and silver flashlights that come in both a large size and a sma
Paladinen [302]

Answer:

D

Step-by-step explanation:

It has all the flashlight colors and sizes.

4 0
3 years ago
Need help with working please
hammer [34]
What do you need help with what question exactly
4 0
3 years ago
Jerome went on a hike. He climbed 3/4 of a mile in 2/3 of an hour. What was his hiking speed in miles per hour?
Anvisha [2.4K]
1 hour = 60 mins 1 mile = 60 mins 3/4 = 45 mins. 2/3 = 40 mins. So 45+ 40 = 1 hour and 25 mins.
6 0
3 years ago
You have quarters and dimes that total $2.80. your friend says it is possible that the number of quarters is 8 more than the num
ss7ja [257]
To answer this question, you need to know that a quarter is worth $0.25 and dimes worth $0.10. In this case, the total number of money that made from quarters and dimes is $2.80
With Q=quarter and D=dime, then the equation should be:
2.80= 0.25 Q + 0.10 D

The condition that needs to be fulfilled in this case is that the quarter should be 8 more than dimes. Then you need to find out the highest possible number of the quarter and lowest possible number of the dimes.  
If you divide 2.8 with 0.25 you will found it will be 11.2 but 11 quarter will result with 0.05 value which you cannot remove, so the highest possible of the quarter should be 10.
If the highest possible of the quarter is 10, then the lowest possible of dimes should be:
2.8= 0.25(10) + 0.10D
0.10D= 0.3
D=3

Since 10-3 is 7, then it is not possible for the quarter to be 8 more than the dimes.
4 0
3 years ago
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