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3 years ago

Please help me with this algebra nation problem!

Mathematics

1 answer:

Darina [25.2K]3 years ago

7 0

Answer:

A= 4x squared

B= 2x squared

C= I think its 7

Step-by-step explanation:

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In the balcony of an auditorium, there are 20 seats in the first row, 22 seats in the second row and 24 seats in the third row.

JulsSmile [24]

Answer:

is two more than the row before

Step-by-step explanation:

i hope i help\

7 0

3 years ago

What is a1 for the geometric sequence for which a8= -3584 and a3 = 112 ?

jasenka [17]

Answer:

The first term is 28.

Step-by-step explanation:

Given: 8th term of Geometric sequence , $a_8=-3584$

and 3rd term of Geometric Sequence, $a_3=112$

We have to find First term of given geometric Sequence.

Let a be the first term of geometric sequence.

We know that,

$a_n=ar^{n-1}$

So,

$\frac{a_8}{a_3}=\frac{ar^{8-1}}{ar^{3-1}}=\frac{-3584}{112}$

$\frac{r^{7}}{r^{2}}=-32$

$r^5=-32$

$r=-2$

So, $a_3=112$

$a\times(-2)^{2}=112$

$a=\frac{112}{4}=28$

Therefore, The first term is 28.

7 0

3 years ago

A grapefruit is 8% heavier than an orange, and an apple is 10% lighter than the orange.By what percentage is the grapefruit heav

shepuryov [24]

To solve this problem you must apply the proccedure shown below:
1. You have that a grapefruit is 8% heavier than an orange and an apple is 10% lighter than the orange. Therefore, let's give a value to the orange as following:
Orange=1 kg
2. Therefore, you have:
Grapefruit=1 kg+(0.08x1 kg)=1.08 kg
Apple=1 kg-(0.1x1 kg)=0.9 kg
3. Therefore, what percentage is the grapefruit heavier than the apple?
%=(0.9/1.08)100-100
%=16.66%
The answer is:16.66%

5 0

4 years ago

Am I'm correct I linked a picture with it

WARRIOR [948]

Answer: B

Step-by-step explanation:

Use the Triangle Theorem.

Now, we have to find every number involved squared.

2² = 4

3.6² = 12.96

Add the given components.

12.96 + 4 = 16.96

Our final answer is 16.96

Best of Luck!

5 0

3 years ago

Read 2 more answers

A city starts with a population of 500,000 people in 2007. Its population declines according to the equation

hjlf

Answer: After 7 years the population will be one-half the initial amount.

Step-by-step explanation:

Given: Initial population = 500,000

The population declines according to the equation:

$P(t) = 500,000e^{ -0.099t}$ , where P is the population in t years later.

One-half the initial amount = 0.5 x 500,000

= 250,000

Put P(t)=250,000, we get

$250000=500000e^{-0.099t}\\\\\Rightarrow\ \frac{500000e^{-0.099t}}{500000}=\frac{250000}{500000}\\\\\Rightarrow\ e^{-0.099t}=\frac12\\\\\Rightarrow\ -0.099t=\ln \left(\frac{1}{2}\right)\\\\\Rightarrow\ t=\frac{1000\ln \left(2\right)}{99}=\frac{1000(0.69314)}{99}\\\\\Rightarrow\ t=7.00148\approx7$

Hence, After 7 years the population will be one-half the initial amount.

5 0

3 years ago