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kvv77 [185]
2 years ago
15

Use the distributive property to create an equivalent expression too 8(2j + 9 + j).

Mathematics
1 answer:
puteri [66]2 years ago
4 0
24j+72 is equivalent
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6/13

Step-by-step explanation:

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Find the derivative from the first principle y=×3
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The derivative of x^3 is 3x^2.... is that what you were looking for?
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A cheetah runs at an average speed of 50 mph between two jungles that are 150 miles apart. An antelope runs at an average speed
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Which equation requires the division property of equality to be solved?
Ymorist [56]

Answer:

A. 201.6 = 11.2f

Step-by-step explanation:

we solve for each unknown to verify which equality will require the division property:

#A. 201.6 = 11.2f

201.6=11.2f\\\\f=\frac{201.6}{11.2}=201.6\div 11.2\\\\=18

Hence, division property used.

#B. 35.4=Z ÷ 3.1

35.4=Z\div 3.1\\\\35.4=\frac{Z}{3.1}\\\\Z=35.4\times 3.1\\\\=109.74

Hence, multiplication property used.

#C. t/3.2=15.1

\frac{t}{3.2}=15.1\\\\t=15.1\times 3.2\\\\=48.32

Hence, multiplication property used.

#D. 201.6 = 11.2+c

201.6=11.2+c\\\\201.6-11.2=c\\\\c=190.4

Hence, subtractionproperty used.

5 0
3 years ago
Read 2 more answers
In a​ study, 36​% of adults questioned reported that their health was excellent. A researcher wishes to study the health of peop
steposvetlana [31]

Answer:

0.3907

Step-by-step explanation:

We are given that 36​% of adults questioned reported that their health was excellent.

Probability of good health = 0.36

Among 11 adults randomly selected from this​ area, only 3 reported that their health was excellent.

Now we are supposed to find the probability that when 11 adults are randomly​ selected, 3 or fewer are in excellent health.

i.e. P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)

Formula :P(x=r)=^nC_r p^r q ^ {n-r}

p is the probability of success i.e. p = 0.36

q = probability of failure = 1- 0.36 = 0.64

n = 11

So, P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)

P(x\leq 3)=^{11}C_1 (0.36)^1 (0.64)^{11-1}+^{11}C_2 (0.36)^2 (0.64)^{11-2}+^{11}C_3 (0.36)^3 (0.64)^{11-3}

P(x\leq 3)=\frac{11!}{1!(11-1)!} (0.36)^1 (0.64)^{11-1}+\frac{11!}{2!(11-2)!}  (0.36)^2 (0.64)^{11-2}+\frac{11!}{3!(11-3)!} (0.36)^3 (0.64)^{11-3}

P(x\leq 3)=0.390748

Hence  the probability that when 11 adults are randomly​ selected, 3 or fewer are in excellent health is 0.3907

5 0
3 years ago
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