You need to solve the equation for h.
<span>W= 50+2.3(h-60)
Distribute the 2.3.
W = 50 + 2.3h - 138
W = 2.3h - 88
Add 88 to both sides.
W + 88 = 2.3h
Switch sides.
2.3h = W + 88
Divide both sides by 2.3.
h = (W + 88)/2.3
</span>
It is given that there are 41 males and 48 females in the small school.
So, the number of ways a male student can be chosen from 41 males is 
Likewise, the number of ways a female student can be chosen from 48 females is
.
Thus, the total number of ways in which 2-person combinations are possible to represent the student body at the PTSAC meetings will be given by:

Answer: add
Step-by-step explanation:
Generally we use n as a counter and begin it with 1: the first term is obtained when n = 1. Thus, n must be a positive integer, 1 or greater: {1, 2, 3, ... }.